p4 + 3O2 ---> 2PO3
Assuming that you are combining the P4 with Cl2 and there is a suffiecient quantity of Cl2 for the P4 to completely react, you will first need a balanced equation which is P4 + 10Cl2 -> 4PCl5. From there, it's mostly stoichiometry. Take the 24g of P4, divide by the molar mass (123.88g/mol) to get the number of moles of P4 that you have (0.194). You then have to convert, using the balanced equation, from moles of P4 to moles of PCl5, in this case multiplying by 4. That will give you the number of moles of PCl5. The stoichiometry should look something like this 24.0 g P4 x (1 mol P4/123.88g P4) x (4 mol PCl5/1 mol P4).
That's a synthesis, or combination reaction. These types of reactions generally have 2 reactants and 1 product.
p4+502=p4010
p + 3 + = -3
P4+Cl2 P4+Cl2
The number of atoms of each element must be the same on both sides of the equation. Therefore, the reaction is as follows: S8 + 8O2 ---> 8SO2 Keep in mind that the subscripts of the products and reactants cannot be changed.
P4 + 5o2 ---> 2p2o5
In an expression p4 is called a term.
the color of P4 is light brown
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P4 binds E1 and deactivates it.