The expression p x p x p x p can be simplified as p^4, where the exponent 4 indicates that p is multiplied by itself 4 times. This means that p^4 is equal to p multiplied by p, and then that result multiplied by p, and then that result multiplied by p one more time. So, p x p x p x p simplifies to p^4.
Oh, what a lovely question! When you multiply p by itself four times, you get p to the power of 4, written as p^4. It's like painting a beautiful landscape with four layers of the same color, creating a harmonious and balanced masterpiece. Just remember, there are endless possibilities when you let your creativity flow like the gentle strokes of a paintbrush on a canvas.
Suppose p(x) is a polynomial in x. Then p(a) = 0 if and only if (x-a) is a factor of p(x).
If: m = n+x/p then x = p(m-n)
That means the same as p times p times p (that is, "p" appears 3 times as a factor).
If the probability of an event x happening is P(x) where P(x) must be greater than or equal to 0 and less than or equal to 1, P(x) can be written as: 1. A decimal, for example P(x)=.5 2. A fraction, for example P(x)=1/2 3. A percent, for example, P(X)=50%.
_______________________________________________________ P = m x v P = momentum m= mass v = velocity _______________________________________________________ P t = P 1 x P 2 Total momentum = Momentum 1 X Momentum 2 Total momentum = ( mass x velocity of the first object ) x ( mass x velocity of the second object )
4p
p2 X p2 = p4or p X p X p X p = p4
p2 X p2 = p4or p X p X p X p = p4
f(x) = P(x)/Q(x) where P(x) and P(x) are polynomials and P(x) is not zero.
Well for one you cant buy Alex Rider the Gemini Project because it doesn't exist what your after is Alex Rider Point Blanc and as for that you can buy it in many places like amazon or got to the libary and get it :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :D :D :D :D :D :D :D :D :D :D :D :D :D :D :D :D :D :D :D :D :D :D :D :D :D :D :D :D :p :p :p :p :p :p :p :p :p :p :p :p :p :p :p :p :p :p :p :p :p :p :p :p :p :p :p :p :p :p :o :o :o :o :o :o :o :o :o :o :o :o :o :o :o :o :o :o :o :o :o :o :o :o :o :o :o :o :o :o :b :b :b :b :b :b :b :b :b :b :b :b :b :b :b :b :b :b :b :b :b :b :b :b :b :b :b :b :b :b :x :x :x :x :x :x :x :x :x :x :x :x :x :x :x :x :x :x :x :x :x :x :x :x :x :x :x :x :x :x :x :x :x :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :)
2 rows of planks going downwards vertically. |P|P|X| |P|P|X| |P|P|X| Where P=plank and X=nothing
x-a is a factor of the polynomial p(x),if p(a)=0.also,if x-a is a factor of p(x), p(a)=0.
P= positive N=negative P x N = N N x P = N P x P = P N x N = P Hope that helps!?!?!
We have to use the expression P(X=x) = nCx px (1--p)(n--x) Here n = n and p=p and x = 1 or x>1 P(X>/=1) = 1 -- P(X</=1) So, P(X<=1) = P(X=0) + P(X=1) This gives nC0 p0 (1--p)(n-0)+ nC1 p1 (1--p)(n--1) ie (1--p)n + n p (1--p)(n--1)
Yes.
Suppose p(x) is a polynomial in x. Then p(a) = 0 if and only if (x-a) is a factor of p(x).
#include <stdio.h> #include <stdlib.h> main(){ int x, *p; p = &x; /* initialise pointer */ *p = 0; /* set x to zero */ printf("x is %d\n", x); printf("*p is %d\n", *p); *p += 1; /* increment what p points to */ printf("x is %d\n", x); (*p)++; /* increment what p points to */ printf("x is %d\n", x); exit(EXIT_SUCCESS);