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Suppose p(x) is a polynomial in x. Then p(a) = 0 if and only if (x-a) is a factor of p(x).
5pr.The specific answer depends on the values of the variables p & r.
If: m = n+x/p then x = p(m-n)
That means the same as p times p times p (that is, "p" appears 3 times as a factor).
If the probability of an event x happening is P(x) where P(x) must be greater than or equal to 0 and less than or equal to 1, P(x) can be written as: 1. A decimal, for example P(x)=.5 2. A fraction, for example P(x)=1/2 3. A percent, for example, P(X)=50%.
4p
p2 X p2 = p4or p X p X p X p = p4
p2 X p2 = p4or p X p X p X p = p4
f(x) = P(x)/Q(x) where P(x) and P(x) are polynomials and P(x) is not zero.
2 rows of planks going downwards vertically. |P|P|X| |P|P|X| |P|P|X| Where P=plank and X=nothing
Well for one you cant buy Alex Rider the Gemini Project because it doesn't exist what your after is Alex Rider Point Blanc and as for that you can buy it in many places like amazon or got to the libary and get it :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :D :D :D :D :D :D :D :D :D :D :D :D :D :D :D :D :D :D :D :D :D :D :D :D :D :D :D :D :p :p :p :p :p :p :p :p :p :p :p :p :p :p :p :p :p :p :p :p :p :p :p :p :p :p :p :p :p :p :o :o :o :o :o :o :o :o :o :o :o :o :o :o :o :o :o :o :o :o :o :o :o :o :o :o :o :o :o :o :b :b :b :b :b :b :b :b :b :b :b :b :b :b :b :b :b :b :b :b :b :b :b :b :b :b :b :b :b :b :x :x :x :x :x :x :x :x :x :x :x :x :x :x :x :x :x :x :x :x :x :x :x :x :x :x :x :x :x :x :x :x :x :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :) :)
x-a is a factor of the polynomial p(x),if p(a)=0.also,if x-a is a factor of p(x), p(a)=0.
P= positive N=negative P x N = N N x P = N P x P = P N x N = P Hope that helps!?!?!
We have to use the expression P(X=x) = nCx px (1--p)(n--x) Here n = n and p=p and x = 1 or x>1 P(X>/=1) = 1 -- P(X</=1) So, P(X<=1) = P(X=0) + P(X=1) This gives nC0 p0 (1--p)(n-0)+ nC1 p1 (1--p)(n--1) ie (1--p)n + n p (1--p)(n--1)
Yes.
Suppose p(x) is a polynomial in x. Then p(a) = 0 if and only if (x-a) is a factor of p(x).
#include <stdio.h> #include <stdlib.h> main(){ int x, *p; p = &x; /* initialise pointer */ *p = 0; /* set x to zero */ printf("x is %d\n", x); printf("*p is %d\n", *p); *p += 1; /* increment what p points to */ printf("x is %d\n", x); (*p)++; /* increment what p points to */ printf("x is %d\n", x); exit(EXIT_SUCCESS);