In order to tell whether a number is a multiple of 3:
A few examples:
924 => 15 => 6, therefore 924 is a multiple of 3.
974 => 20 => 2, therefore 974 is not a multiple of 3.
A number that is divisible by 6 but not by 3 must be a multiple of 6 that is not a multiple of 3. Since 6 is a multiple of 3 (6 = 2 * 3), any multiple of 6 will also be a multiple of 3. Therefore, there is no number that is divisible by 6 but not by 3.
you add up the digits, and if the sum is a multiple of 3, then the number is divisible by 3!
Any multiple of 6 is a multiple of 3 and 6.
9 is a multiple of 3. It is 3 x 3.
The third multiple of 3 can be calculated by multiplying 3 by 3, which equals 9. In this case, the third multiple of 3 is 9. In general, to find the nth multiple of a number, you would multiply the number by n.
No. However, one you you can tell is that the digits of a multiple of 3 always add up to another multiple of 3.
If the digits of the number you're dividing by 3 add up to a multiple of 3, the whole number is divisible by 3 and there will be no remainder. If they don't add up to a multiple of 3, there will be a remainder.
If the sum of the digits is a multiple of 3, the whole number is divisible by 3.
I'm not sure what would be a trick for the number 3. I will presume you would mean the way to tell if a number is a multiple of 3. A number is a multiple of 3 if the sum of its digits is also a multiple of 3. For example 585 is a multiple of 3 since' 5+8+5 = 18 which is a multiple of 3. The number 47 is not a multiple of 3 because 4+7 equals 11 and that is not a multiple of 3. There is a second digit that has a similar rule for multiplicity. That digit is 9, which just happens to equal 32 . In fact, since 18 is a multiple of 9, 585 must be a multiple of 9 also.
It would help to have that other number. If the other number is a multiple of 3, the LCM is that number. If it is not a multiple of 3, the LCM is 3 times that number.
You can tell if the number ends in either 5 or 0
Add up the digits in a number, and if that sum is a multiple of 3, then the original number is also a multiple of 3. So 1 + 8 + 9 = 18, which if you're still not sure then 1+8=9, which is a multiple of 3. You can repetitively sum the digits until you have a result of a single digit number. If the single digit result is 3,6 or 9, then the original number is a multiple of 3. Also, if the single digit number is 9, then the number is also a multiple of 9. However, if the result is 6, then it is not necessarily a multiple of six.
yes, it is. A very easy way to tell if a number is a multiple of 3 or not, is to add up the digits of the number and see if you can divide it by 3 evenly or not. So 7965, 7+9+6+5 = 27, and 27 divided by 3 is 9..... =)
No, 92 is not a multiple of 3. A quick way to check if a number is a multiple of 3 is: add up the digits of the number you are checking; if this sum equals 3 or a multiple of 3, then the number is a multiple of 3. So in this case, 92 --> 9+2=11, which is not a multiple of 3. If you have to you can add again, so for 11 --> 1+1=2, which is not a multiple of 3. You can always repetitively add until you get to a single digit answer: if it's 3,6 or 9 then it's a multiple of 3. Also if your sum is 9 or a multiple of 9, then the original number is a multiple of 9. To check for 6, if a number is a multiple of 3, and also a multiple of 2 (an even number), then the number is a multiple of 6.
No. To find if a number is a factor of 3, add the number's digits. If the resulting number is a multiple of 3, then the original number is a multiple of 3. In 4339, the digits of the number added together is 19, which is not a multiple of 3.
you add up the digits, and if the sum is a multiple of 3, then the number is divisible by 3!
3 is the smallest number that is a factor 66 and a multiple of 3