A z table is used to calculate the probability of choosing something that is normally distributed. In order to use it, first a z score is needed. A z score is the number of standard distributions a value is away from the mean of the data. In order to find the z score, take the value of the datum, subtract the mean, then divide by the standard deviation. The result is a z score. Look up the z score on the table to find the probability of getting anything equal to or lesser than the value you chose.
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See the attached link. The area that is read from the table is 1 - .9066 or .0934. Go to the body of the table for the value .0934 and the answer is -1.32. Therefore Z = -1.32.
Since the normal distribution is symmetric, the area between -z and 0 must be the same as the area between 0 and z. Using this fact, you can simplify this problem to finding a z such that the area between 0 and z is .754/2=.377. If you look this value up in a z-table or use the invNorm on a calculator, you will find that the required value of z will be 1.16. Therefore, the area between -1.16 and 1.16 must be approximately .754.
You can use a table or a graph to organize you findings.
1.555 With 88% confidence, there is 6% (0.06) in either tail of the standard Normal distribution. Table C will not help here. Using Table A the correct z* is about halfway between 1.55 and 1.56. According to technology, z*=1.555
From the table in the related link, the value at z equal one is 0.3413. The area then to the right of z equal one is 0.5 - 0.3413, or 0.1587.