The general form is: (A+B)(C+D) = AC + AD + BC + BD
Where AC is the first, AD is the outer, BC is the inner, and BD is the last.So:
(X+4)(X-5)
= X^2 - 5X + 4X - 20
= X^2 - 1X - 20
Foil
binomials
-FOIL Method -Special Products -Geometry It's depends on you :)
it usually starts with x=.... ex: for foil method , which is (a+b)2 would be x=a2+2ab+b2
Squaring a binomial is just a mater of taking the binomial times itself, for example(a+b)2=(a+b)*(a+b)Here you apply FOIL technique, meaning: First, Outer, Inner and Last -- see below(a*a)+(a*b)+(b*a)+(b*b)Observing that (a*b)=(b*a) in alegbra the above equation can be rewritten as:a2+2ab+b2yeah!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!thank you for watching wowowee@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@ the "F.O.I.L" way is the best solution and the easiest!
To find the factor of 2 binomials
It is only not needed if you know of another method. If FOIL is the only way you know to multiply two binomials, then it is definitely needed.
The foil method in algebra is used to "multiply linear binomials."The FOIL method is used in elementary algebra as a guide for solving algebraic problems.
Foil
multiplying
binomials
does the FOIL system work for any binomials
The foil method is a straightforward way to multiply two binomials quickly and accurately. It ensures all terms in the product are accounted for by multiplying each term in the first binomial by each term in the second binomial. This method is especially useful when dealing with simple polynomial multiplication.
You use the FOIL method. First terms Outer terms Inner terms Last terms.
Explain how I would use algebra times to multiply two binomials (FOIL)?
The product of (n - 8)(n + 2) can be found using the distributive property (also known as the FOIL method for binomials). Multiplying the terms gives: n² + 2n - 8n - 16. Combining like terms results in the expression n² - 6n - 16.
ONE WORD...FOIL. The FOIL method is a way to multiply binomials. "FOIL" is an acronym to remember a set of rules to perform this multiplication. To FOIL you multiply together all of the following: * F: Firsts * O: Outers * I: Inners * L: Lasts and then you add each of these products as demonstrated in the examples below. Let's take two arbitrary binomials. (x+a)(x+b) First: x^2 Outers: bx Inners: ax Last: ab So the product of these two binomials is x^2+bx+ax+ab Which we can simplify as x^2+x(a+b)+ab This is NOT the only way, another way is as below: (x+a)(x+b) Start with the x in x+a and multiply it by both terms in x+b so we have x^2+xb Now do the same with the a in x+a and we have ax+ab Add these all together and you have the same result as you did with the foil method. So why not just use foil? Why have two methods when one is plenty? GOOD QUESTION! The second method can be generalized to trinomials or any other types of polynomial multiplication and the FOIL method can't be.