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You have to look at the information given in the question.

It says it's a square so that means that each side is 5 cm long. the area of a square with 5 cm long sides is 25 cm squared.

THAT IS THE FOURTH MATHS QUESTION I'VE ANSWERED TODAY. GO ME!

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Q: How do you work out the area of a square with its perimeter 20cm?
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Related questions

How do you work out perimeter and area?

It is different for each shape. A perimeter is the distance around an object and the area is the square units it takes up.


What is the perimeter of a square with each area of 16 cm squared?

To find the perimeter of a square, you first need to work out the side length. The area of a square is L2 where L is the side length. The area of the square in the question is 16cm2 so L is the square root of 16, or 4. To get the perimeter of the square, we simply multiply the side length by 4. In this case 4x4=16, so the perimeter of the square is 16cm.


How do you work out what the perimeter of a square is with an area of 49cm2?

Area of a square = (length of one side)249 cm2 = (length of one side)27 cm = length of one side========================Perimeter of a square = distance all the way around itPerimeter = (4) x (length of one side)Perimeter = (4) x (7 cm) = 28 cm


What are the dimensions of a rectangle that has a perimeter of 44 units and an area of 105 square units?

The dimensions work out as 7 units and 15 units


What is the area and perimeter of a rhombus whose diagonals are in lengths of 7.5 cm and 10 cm showing work?

Area of the rhombus: 0.5*7.5*10 = 37.5 square cm Perimeter using Pythagoras: 4*square root of (3.75^2 plus 5^2) = 25 cm


What are the dimensions of a rectangle that has a perimeter of 19.8 cm and an area of 24.3 square cm showing work?

Divide the perimeter by 2 then find two numbers that have a sum of 9.9 and a product of 24.3 which will work out as 5.4 and 4.5 by using the quadratic equation formula. Check: 2*(5.4+4.5) = 19.8 cm which is the perimeter Check: 5.4*4.5 = 24.3 square cm which is the area Therefore the dimensions of the rectangle are: 5.4 cm and 4.5 cm


How do you calculate perimeter in acres?

There is no one answer, it depends on the shape. The smallest value of perimeter will be for a circle. For a four sided shape the smallest will be for a square, for a rectangle the perimeter gets bigger the longer and narrower the area becomes. Knowing the area in acres gives the number of square yards only, you have to know either the length or width, work out the width or length as the case may be, then just add up the four sides.


How do you do perimeter and area of L?

Area: Find some of the lengths, then cut the L in half and work it out from there. Perimeter: Add all the lengths together.


What is the area and perimeter of a right angle triangle whose hypotenuse is 35.9 cm with one side greater than the other side by 7.18 cm?

Using Pythagoras' theorem and the quadratic equation formula they work out as:- Area: 309.3144 square cm Perimeter: 86.16 cm


What is the new perimeter of a right angle triangle whose shorter sides are 3cm by 4cm when its sides are doubled gives it an extra area of 18 square cm show work?

Forget about the area and use Pythagoras' theorem: 62+82 = 100 and the square root of this is 10 New perimeter = 6+8+10 = 24 cm


What is the area of a rhombus when one of its diagonals is 11.8 cm in length and has a perimeter of 29 cm showing work and answer?

Perimeter = 29 cm so each side is 7.25 cm. The triangle formed by the diagonal and two sides has sides of 7.25, 7.25 and 11.8 cm so, using Heron's formula, its area is 24.9 square cm. Therefore, the area of the rhombus is twice that = 49.7 square cm.


How do you find the area of a rectangl if you only have the perimeter?

With great difficultly. The area could be any value greater than 0 units2 and less than or equal to the area of a square with the given perimeter which would be 1/16 x perimeter2 units2. To know which of the possible areas you would need to know the length of one side, then you can work out the area: perimeter = 2 x (length + width) ⇒ width = (1/2 x perimeter) - length ⇒ area = length x width = length x ((1/2 x perimeter) - length) = (1/2 x perimeter x length) - length2