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Restate the question: How do you complete the square when the coefficient of the x-term is odd?

If this is not your question, please clarify and resubmit the question. :-)

Compare x2 +bx+c with (x+a)2 = x2 +2ax +a2: b has to equal 2a, which gives a = b/2. . . . For example: Add a constant term to x2 +7x to make a perfect square. b=7, so a=7/2. You have to add (7/2)2 =72/22 = 49/4. . . . x2 + 7x + 49/4 = (x+7/2)2.

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