Restate the question: How do you complete the square when the coefficient of the x-term is odd?
If this is not your question, please clarify and resubmit the question. :-)
Compare x2 +bx+c with (x+a)2 = x2 +2ax +a2: b has to equal 2a, which gives a = b/2. . . . For example: Add a constant term to x2 +7x to make a perfect square. b=7, so a=7/2. You have to add (7/2)2 =72/22 = 49/4. . . . x2 + 7x + 49/4 = (x+7/2)2.
Write it in the form ax2 + bx + c. It is a perfect square if b2 = 4ac
the degree of trinomial is the sum of the variables exponents
You ignore the constant part (-3 in this case), calculate half of the coefficient of the linear part (8, in this case), and square this half. (1/2 of 8 is 4; the square of 4 is 16). This gives you the perfect square x2 + 8x + 16. To get something equivalent to the original expression, you must both add and subtract 16, and include the term which I previously ignored (-3): x2 + 8x + 16 - 16 - 3, which you can write as (x2 + 8x + 16) - 16 - 3. The part within parentheses is the perfect square.
100 is a perfect square. If you divide this into 2100 you are left with 21.21 is 3 x 7. Three and seven are two different prime numbers.You can't get a perfect square out of that, so the answer is :-Dividing by 21 gives you a perfect square.Dividing by any smaller number would leave an unpaired and unpairable prime number in the quotient.
Multiplying a number by its self is called squaring a number When using exponents, the second power of a whole number is called a perfect square too, For example, write 4 squared = 16, 7 squared = 49, and 265 = 70, 225 are all perfect squares.
Write it in the form ax2 + bx + c. It is a perfect square if b2 = 4ac
A perfect square trinomial is looking for compatible factors that would fit in the last term when multiplied and in the second term if added/subtracted (considering the signs of each polynomials).* * * * *A simpler answer is: write the trinomial in the form ax2 + bx + c. Then, if b2 = 4ac, it is a perfect square.
The way we create a perfect square trinomial is by squaring something in the form of (x-a) where a is some real number. For example (x-2)2 is x2 -4x+4 which is a perfect square trinomial. Not, write this as (x-2)(x-2) instead of (x-2)2 . To find the solutions, we write (x-2)(x-2)=0 The only solution that will make the left side equal to zero is 2. So in general, if we have a perfect square trinomial with the unknown as x, think of it as (x-a)2 or as (x-a)(x-a), then if we set this to 0, the one and only solution is x=a
You cannot because it is not a perfect square.
the degree of trinomial is the sum of the variables exponents
9
Any integer ,n, to the 6th. power would be both a perfect square and a perfect cube: This is because (n2 )3 =n6 which is a perfect square and a perfect cube. Or course you could also write this as (n3 )2 =n6 06 = 0 16 = 1 26 = 64 etc.
When you're asked to simplify the square root of something that isn't a perfect square like 25 or 16, look for perfect square factors within the number. For example, 75 can be written as 25x3. I'm sure you know 25 to be 5x5, the perfect square of 5. Now we can write 75 as 52x3. Since we're taking the square root, 52 gets moved out of the square root and you can write the final answer as 5 times the square root of 3, the factor that's left. Final answer: 5sqrrt3
You ignore the constant part (-3 in this case), calculate half of the coefficient of the linear part (8, in this case), and square this half. (1/2 of 8 is 4; the square of 4 is 16). This gives you the perfect square x2 + 8x + 16. To get something equivalent to the original expression, you must both add and subtract 16, and include the term which I previously ignored (-3): x2 + 8x + 16 - 16 - 3, which you can write as (x2 + 8x + 16) - 16 - 3. The part within parentheses is the perfect square.
You first find a factor of 125 that is also a perfect square. It is 25. Then, write 125 as 5(25). Then, square root the 25, and therefore your answer is 5*sqrt5.
The future perfect form of "write" is "will have written."
It is 3.