You cannot because it is not a perfect square.
No, 1728 is not a perfect square. The square root of 1728 is 41.569, which is not an integer. Therefore, since it cannot be expressed as the product of an integer multiplied by itself, 1728 does not qualify as a perfect square.
Write it in the form ax2 + bx + c. It is a perfect square if b2 = 4ac
1728 square feet
144 square feet
12 square feet
9
36'x48'=1728 square feet.
24√3 or 41.5692194 or 41.57, to the justified number of significant digits since 1728 has only four.
Any integer ,n, to the 6th. power would be both a perfect square and a perfect cube: This is because (n2 )3 =n6 which is a perfect square and a perfect cube. Or course you could also write this as (n3 )2 =n6 06 = 0 16 = 1 26 = 64 etc.
Out of the factor pairs of 1728, only 144 and 12 have a square/square root relationship. 12 has to be the cube root of 1728. (1728,1)(864,2)(576,3)(432,4)(288,6)(216,8)(192,9)(144,12)(108,16)(96,18)(72,24)(64,27)(54,32)(48,36)
200 is not a perfect square. Its square root is a fraction and the square root of a perfect square is always an integer.
No, 325 is not a perfect square however 324 is a perfect square.