r+r+r+r+r=10 therefore, r must equal two
pq-r, if p is 3, q is 4, and r is -6 is equal to 3 x 4 - (-6), which is equal to 12 + 6, which is equal to 18.
-4r = 8Divide each side of the equation by -4 :r = -2
If: d = 60 times 4 then d = 240
The answer is 123 4/12 or
r+r+r+r+r=10 therefore, r must equal two
pq-r, if p is 3, q is 4, and r is -6 is equal to 3 x 4 - (-6), which is equal to 12 + 6, which is equal to 18.
-4r = 8Divide each side of the equation by -4 :r = -2
a could equal 0 and r could equal 27a could equal 1 and r could equal 23a could equal 2 and r could equal 19a could equal 3 and r could equal 15a could equal 4 and r could equal 11a could equal 5 and r could equal 7a could equal 6 and r could equal 3a could equal 7 and r could equal - 1It could be any of these and many, many more...is it the whole question?
r = 4
Given: Radius, r=4 Area, A=(22/7)*r*r A=(22/7)*4*4 A=50.2857 sq. units
r/4
4
5 divided by 4 is equal to 1 and a quarter which is also equal to 1.25.
Could be (r + 8)/2 or r/2 + 4
4.3333
You write an equal sign; you write something to the left of the equal sign; and you write something to the right of the equal sign. For example: x = 3 x = y 3 = 3 0 = 4 1 + 2 = 5 etc.