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Suppose f = 0.3111...

then 10f = 3.111....

Subtracting the second from the first, 9f = 2.8

so that f = 2.8/9 = 28/90 which simplifies to 14/45

Suppose f = 0.3111...

then 10f = 3.111....

Subtracting the second from the first, 9f = 2.8

so that f = 2.8/9 = 28/90 which simplifies to 14/45

Suppose f = 0.3111...

then 10f = 3.111....

Subtracting the second from the first, 9f = 2.8

so that f = 2.8/9 = 28/90 which simplifies to 14/45

Suppose f = 0.3111...

then 10f = 3.111....

Subtracting the second from the first, 9f = 2.8

so that f = 2.8/9 = 28/90 which simplifies to 14/45

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11y ago

Suppose f = 0.3111...

then 10f = 3.111....

Subtracting the second from the first, 9f = 2.8

so that f = 2.8/9 = 28/90 which simplifies to 14/45

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Q: How do you you express 0.31111111111111 recurring as a common fraction?
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