For the equilateral triangle in Euclidean space(i.e, the triangles you see in general) median is the same as its altitude. So, both are of equal length.
The altitude/height of an equilateral triangle can be calculated by taking the perpendicular bisector of any side. This line will bisect its opposite angle forming two congruent right angled triangles. The side length of the original equilateral triangle is the hypotenuse and the short leg of right angled triangle is half the hypotenuse. By Pythagoras' Theorem : 42 = 22 + L2.........where L is the length of the altitude. L2 = 42 - 22 = 16 - 4 = 12 L = √12 = 2√3 = 3.464 (3dp)
9.794747317 m (with the help of Pythagoras' theorem)
is called an equilateral triangle
Using Pythagoras' theorem it works out as 10.5 units of measurement
No. The altitude is smaller.
Given an altitude of 12 units, an equilateral triangle has side lengths of 13.9 (13.85641) units.
For the equilateral triangle in Euclidean space(i.e, the triangles you see in general) median is the same as its altitude. So, both are of equal length.
Each side of the triangle is 16.16581 units in length.
Given side lengths of 8 units, an equilateral triangle will have an altitude of 7 (6.9282) units.
With an altitude of 10 units, this triangle's sides each measure 11.55 (11.54701) units.
The sides are 2*sqrt(3) units in length.
It is double the length of the base, in square units.
Multiply the altitude by [ 2 / sqrt(3) ] to get the length of the side.[ 2 / sqrt(3) ] is about 1.1547 (rounded)
Height = sqrt(3)/2 * length of side So here, approx 4.3301 cm
The length of each side is 9.2376 cm. (rounded)
The altitude forms a right angle triangle with half the side length and one side as the hypotenuse. Using Pythagoras: (½side)² + altitude² = side² → altitude² = side² - ¼side² → altitude² = ¾side² → altitude = (√3)/2 × side → altitude = (√3)/2 × 6 = 3√3 ≈ 5.2