Let y=ce^(rx). R^2+r+1=0. Quadratic equation to find R.
y"+y'=0 is a differential equation and mean the first derivative plus the second derivative =0.Look at e-x the first derivative is -e-xThe second derivative will be e-xThe sum will be 0
it is a prime number
Nothing equals 101 except for 1*101...101 is prime!
double prime symbol ( ″ ),
To find the multiplication that equals 74, we need to factorize 74 into its prime factors. 74 can be expressed as 2 x 37. Therefore, the multiplication that equals 74 is 2 multiplied by 37.
There are no prime factors in that equation.
y"+y'=0 is a differential equation and mean the first derivative plus the second derivative =0.Look at e-x the first derivative is -e-xThe second derivative will be e-xThe sum will be 0
To find a multiplication equation with prime numbers that equals 84, we need to break down 84 into its prime factors. 84 can be expressed as 2 x 2 x 3 x 7. Therefore, a multiplication equation with prime numbers that equals 84 is 2 x 2 x 3 x 7.
70 equals 70, and it is not prime.70 equals 70, and it is not prime.70 equals 70, and it is not prime.70 equals 70, and it is not prime.
The "double prime", or second derivative of y = 5x, equals zero. The first derivative is 5, a constant. Since the derivative of any constant is zero, the derivative of 5 is zero.
"Double prime" is a term used in calculus. I have found no information on anything called a "double prime number".
The prime factorization of 1225 is 5x5x7x7.
2310
7 is already prime. It has no factorization.
relatively prime, or co-prime.
No.
its2x2x2x2x3x5x5