Let y=ce^(rx). R^2+r+1=0. Quadratic equation to find R.
There are no prime factors in that equation.
y"+y'=0 is a differential equation and mean the first derivative plus the second derivative =0.Look at e-x the first derivative is -e-xThe second derivative will be e-xThe sum will be 0
To do prime factorization, you need to find the equation that equals up to the number. For example, if the number is 1,125, the prime factoraztion would be 3x3x5x5x5.
70 equals 70, and it is not prime.70 equals 70, and it is not prime.70 equals 70, and it is not prime.70 equals 70, and it is not prime.
The "double prime", or second derivative of y = 5x, equals zero. The first derivative is 5, a constant. Since the derivative of any constant is zero, the derivative of 5 is zero.
2 x 2 x 3 x 7 = 84
"Double prime" is a term used in calculus. I have found no information on anything called a "double prime number".
The prime factorization of 1225 is 5x5x7x7.
37 is a prime number, so 1 x 37 is the only equation using whole numbers that can produce 37.
13 because it is a prime number
2310
7 is already prime. It has no factorization.