x = 0 and y = 4
y equals negative 8.
y equals x plus 4 when y equals 0 then x equals 2i i is the square root of negative 1
y2 +8y + 16 = 0 can factor to (y+4) (y+4) = 0 so y+4 = 0 so y = -4
x + y + z = 0 x = a - b, y = b - c, z = c - a, therefore a - b + b - c + c - a = ? a - a + b - b + c - c = 0
x = y = 0 ?
a = 3 and y = 0
-y + y equals 0.
(0, -3)
y = 0x = y + 2plug 0 in for yx = 0 + 2x = 2
y = 6
many solutions
(11, 1, 0) and (0, 1, 11) are the two possible solutions.
The fact that 0 is the additive identity.
y= -2x
x = 0 and y = 4
That's the identity property of addition. Anything plus zero equals what you started out with.