y"+y'=0 is a differential equation and mean the first derivative plus the second derivative =0.
Look at e-x the first derivative is -e-x
The second derivative will be e-x
The sum will be 0
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x = 0 and y = 4
y equals negative 8.
y equals x plus 4 when y equals 0 then x equals 2i i is the square root of negative 1
y2 +8y + 16 = 0 can factor to (y+4) (y+4) = 0 so y+4 = 0 so y = -4
x + y + z = 0 x = a - b, y = b - c, z = c - a, therefore a - b + b - c + c - a = ? a - a + b - b + c - c = 0