idk
f(x) = 2x5 + 5x4 - 2x3 - 7x2 -4x - 12 We use the Leading Coefficient Test to determine the graph's end behavior. Because the degree of f(x) is odd (n = 5) and the leading coefficient, 2, is positive, the graph falls to the left and rises to the right.
Most graphs will become steeper as the coefficient increases.
For a straight line graph, if the equation of the graph is written is the slope-intercept form, then the line goes up and to the right when the coefficient of x is positive.
Leading coefficient: Negative. Order: Any even integer.
It gets reflected in the x-axis.
the left end of the graph is going in a positive direction and the right end is going in a negative direction.
what is the leading coefficient -3x+8
The answer depends on the what the leading coefficient is of!
f(x) = 2x5 + 5x4 - 2x3 - 7x2 -4x - 12 We use the Leading Coefficient Test to determine the graph's end behavior. Because the degree of f(x) is odd (n = 5) and the leading coefficient, 2, is positive, the graph falls to the left and rises to the right.
It is the coefficient of the highest power of the variable in an expression.
Most graphs will become steeper as the coefficient increases.
For a straight line graph, if the equation of the graph is written is the slope-intercept form, then the line goes up and to the right when the coefficient of x is positive.
It is the number (coefficient) that belongs to the variable of the highest degree in a polynomial.
Idk
For a polynomial of order n there are n+1 coefficients that can be changed. There are therefore 2^(n+1) related polynomials with coefficients of the same absolute values. All these generate graphs whose shapes differ.If only the constant coefficient is switched, the graph does not change shape but moves vertically. If every coefficient is switched then the graph is reflected in the horizontal axis. For all other sign changes, there are intermediate changes in the shape of the graph.