The internal angles of a polygon with n vertices sum to (n-2)*180 degrees. This is easy to prove given a browser that supports very basic graphics but this one is just not fit for that!
Then, since an octagon has 8vertices, its interior angles sum to (8-2)*180 = 6*180 = 1080 degrees.
The 8 interior angles of an octagon add up to 1,080 degrees.
The interior angles of an octagon sum to 6*pi radians (1080 degrees).
A 10 sided polygon or a decagon has interior angles that add up to 1440 degrees
1440 degrees. The sum of the interior angles of any regular polygon of n sides is equal to 180(n - 2) degrees.
The answer is 11 sides If a polygon with 10 sides the sum of the interior angles are 1440° So 1440°+180°= 1620°
Sum of exterior angles = 360 degrees Sum of interior angles = 1440 degrees
The 8 interior angles of an octagon add up to 1,080 degrees.
The sum of the interior angles of an octagon is equal to 1080 degrees.
The sum of the interior angles of a decagon is 1440 degrees The sum of the interior angles of a triangle is 180 degreesThe difference in the sum of the interior angles of a decagon compared to a triangle = 1440 degrees minus 180 degrees = 1260 degrees
The sum of the interior angles is 8x180 degrees or 1440 degrees. The sum of the exterior angles is always 360 degrees.
1080 degrees
1080 degrees.
An octagon has 8 sides and 8 angles. The sum of the interior angles of an octagon is 1080 degrees.
A decagon
1440 degrees
1440 degrees
The sum of the interior angles is 1440 degrees.