The answer is 11 sides If a polygon with 10 sides the sum of the interior angles are 1440° So 1440°+180°= 1620°
If the interior angle measures 1440 you have a serious problem. If the sum of the interior angles is 1440, then the question can be answered as follows: The sum of the interior angles of a n-gon is (n-2)*180 degrees So (n-2)*180 = 1440 So that n-2 = 8 and so n = 10
144 degrees; sum of interior angles in a polygon = (n-2)180 degrees. 180(18)=1440. 1440/10=144. (n=no. of sides.)
Theorem 6-1-2; Polygon Exterior Angle Sum Theorem:The sum of the exterior angle measures, one angle at each vertex, of a convex polygon is 360 degrees.
1440 degrees. The total exterior angles of a polygon is always 360 deg. Each interior angle plus its corresponding exterior angle is 180 deg. The sum of all interior plus all interior for a decagon must therefore be 1800 deg. Hence sum of interior angles is: 1800-360=1440 deg.
1440 degrees
1440 degrees
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The polygon would have 10 sides.
A polygon with 10 sides is called decagon and the sum of the interior angles is 1440 degrees. (10-2)180=1440
The answer is 11 sides If a polygon with 10 sides the sum of the interior angles are 1440° So 1440°+180°= 1620°
The sum of the interior angle measures=(the number of sides-2) times 180. So 1440=(n-2)180. 180n-360=1440 180n=1800 n=10 The polygon has 10 sides.
10 sides
1800 the correct answer is 1440 degrees. Apex geometry 2nd Sem. -- 1800 degrees.
sum of external angles of a polygon is always 360° sum of 10 external angles = 360° each exterior angle = 360/10 = 36° exterior angle and interior angle forms a linear pair i.e. = 180° interior angle = 180 - 36 = 144° sum of exterior angles of polygon is = (n - 2) × 180° = (10 - 2) × 180 = 1440° so each interior angle = 1440/10 = 144° ---------