The simple is to calculate the volume of the cone and subtract from the result the volume of the cone whose altitude is 1/2 the altitude of the original cone. This is easier said than done. The volume of a cone with circular base is (1/3)πr2s where r is the radius of the base and s is the altitude. The radius of the base of the empty part of the cone and hence its area can be found by using the pythagorean theorem
I don't think there is a special name for that.
A full turn has 360% to fine a half of something we divide by 2 360/2=180 there are 180 in a half of a full turn
How many faces, edge and vertex in cone
a half pint, or 10 fl oz.
It depends on what size bathtub you have.
You simply calculate it like a cone, but the height of the cone is the height to the top of the FILLED part, not all the way. Half-filled is not enough information . . . there can be "half filled" meaning half the height of the cone, but can also be "half filled" meaning half the volume of the cone.
it a cone cut in half from the top
Calculate the volume of a full sphere, then divide that by 2.
VariablesD = Cylinder diameter [L].Dbot = Cone bottom diameter [L].Dtop = Cone top diameter [L].h = Cone height [L].L = Cylinder length [L].T = Top width of liquid in cylinder [L].y = Liquid depth in sphere or cylinder [L].z = Horizontal to vertical side slope of cone. zDbot.Ø = Angle representing how full the cylinder is [radians or degrees]. An empty cylinder has Ø=0o, a cylinder with Ø=180o is half full, and a cylinder with Ø=360o is completely full.
Usually they are full or half seasons.
If the mass of a substance is cut in half but the volume remains the same, the density of the substance would also be cut in half. This is because density is calculated by dividing mass by volume, so reducing the mass will directly affect the density without changing the volume.
Half of its diameter
Volume of each cone: 1/3*pi*32*19 = 57*pi cubic cm 5/8 of 57*pi is about 112 cubic cm
The answer to this is pretty straightforward. First, the volume a tank measuring 100 by 40 by 60 cm is 100x60x40cm = 240,000 cm^3 or cubic cm. Since one liter = 1000 cm^3, the total tank volume is thus 240 liters. If the tank is half full, then simply halve the amount of water so the tank would contain 120 liters if half full. The same approach can be used for any tank or container assuming it's volume is known, or can be calculated.
pebble has volume so water rises equal to volume of pebble
nappe :)
It is called a frustum.