3
There are 0 eight's in three, but there are two and two third threes in eight. Hope this helps :)
8 can go into 24 3 times, right? 8 + 8 = 16, then + 8 = 24. So one 8 over three 8s is the same as 8/24 and 1/3.If that doesn't help, you could also work it out just by dividing both parts of the fraction by the same thing, in this case, 8. 8 divided by 8 = 1, and 24 divided by 8 = 3.1/3 is the simplest because you can't reduce it farther than that.
2
1 and 1 over 3
33, with 3 left over
3
3
1
11 whole eights, with 6 left over. The 6 will make 3/4 of another eight.
There are 0 eight's in three, but there are two and two third threes in eight. Hope this helps :)
3 quarters 2 thirds 1 quarter 2 eighths which is the same as 1 quarter
3 of them with a remainder of 4 or 28/8 = 3.5
8 - 8/8 = 8 - 1 = 7
A = (s, 2s), B = (3s, 8s) The midpoint of AB is C = [(s + 3s)/2, (2s + 8s)/2] = [4s/2, 10s/2] = (2s, 5s) Gradient of AB = (8s - 2s)/(3s - s) = 6s/2s = 3 Gradient of perpendicular to AB = -1/(slope AB) = -1/3 Now, line through C = (2s, 5s) with gradient -1/3 is y - 5s = -1/3*(x - 2s) = 1/3*(2s - x) or 3y - 15s = 2s - x or x + 3y = 17s
27 / 8
Points: (s, 2s) and (3s, 8s) Slope: (8s-2s)/(3s-s) = 6s/2s = 3 Perpendicular slope: -1/3 Midpoint: (s+3s)/2 and (2s+8s)/2 = (2s, 5s) Equation: y-5s = -1/3(x-2s) => 3y-15s = -1(x-2s) => 3y = -x+17x Perpendicular bisector equation in its general form: x+3y-17s = 0