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How many 1/8 fractions are in 3? Answer 24.
There are eight 1/8 fractions in 1.
That's because 8 x 1/8 = 8/8 = 1
So there are 24 1/8 fractions in 3.
24 x 1/8 = 24/8
24/8 means: 24 divided by 8 which equals 3
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∙ 12y ago
Tanayja Griffith
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How many 8s go into 24?
3
How is 8 over 24 in simplest form 1 over 3?
8 can go into 24 3 times, right? 8 + 8 = 16, then + 8 = 24. So one 8 over three 8s is the same as 8/24 and 1/3.If that doesn't help, you could also work it out just by dividing both parts of the fraction by the same thing, in this case, 8. 8 divided by 8 = 1, and 24 divided by 8 = 3.1/3 is the simplest because you can't reduce it farther than that.
How many fourths are in seven over eight?
2
What is 2 minus 2 over 3?
1 and 1 over 3
What is the reciprocal of 3 and 1 over 5?
5 over 3 and 1
How many 8s are in 267?
33, with 3 left over
How many 8s go into 24?
3
How many 8s are you 24?
3
What is 4 - 3 eights?
1
How many 8s can you make out of 94?
11 whole eights, with 6 left over. The 6 will make 3/4 of another eight.
How many is 3 over 4 How many is 2 over 3 How many is 1 over 4 How many is 2 over 8 How many is 1 over 2 How many is 1 over 3?
3 quarters 2 thirds 1 quarter 2 eighths which is the same as 1 quarter
How many 8s go into 28?
3 of them with a remainder of 4 or 28/8 = 3.5
How can you use 3 8s to equal 7?
8 - 8/8 = 8 - 1 = 7
How do you determine the equation for the perpendicular bisector of the straight line joining the points s 2s and 3s 8s?
A = (s, 2s), B = (3s, 8s) The midpoint of AB is C = [(s + 3s)/2, (2s + 8s)/2] = [4s/2, 10s/2] = (2s, 5s) Gradient of AB = (8s - 2s)/(3s - s) = 6s/2s = 3 Gradient of perpendicular to AB = -1/(slope AB) = -1/3 Now, line through C = (2s, 5s) with gradient -1/3 is y - 5s = -1/3*(x - 2s) = 1/3*(2s - x) or 3y - 15s = 2s - x or x + 3y = 17s
What is the improper answer to 3 and 3 8s?
27 / 8
What is the perpendicular bisector equation joining the points of s 2s and 3s 8s on the Cartesian plane showing work?
Points: (s, 2s) and (3s, 8s) Slope: (8s-2s)/(3s-s) = 6s/2s = 3 Perpendicular slope: -1/3 Midpoint: (s+3s)/2 and (2s+8s)/2 = (2s, 5s) Equation: y-5s = -1/3(x-2s) => 3y-15s = -1(x-2s) => 3y = -x+17x Perpendicular bisector equation in its general form: x+3y-17s = 0
What is the perpendicular bisector equation of a line joined by the points of s 2s and 3s 8s showing key stages of work?
It is found as follows:- Points: (s, 2s) and (3s, 8s) Slope: (2s-8s)/(s-3s) = -6s/-2s = 3 Perpendicular slope: -1/3 Midpoint: (s+3s)/2 and (2s+8s)/2 = (2s, 5s) Equation: y-5s = -1/3(x-2s) Multiply all terms by 3: 3y-15s = -1(x-2s) => 3y = -x+17s In its general form: x+3y-17s = 0
