TEN of course !
7/1.4 = 5 lengths.
20 meters.2m/6sec = x/60secx = (2m*60sec)/6secx = 20m
It is: 200/8 = 25
The triangle with side lengths of 2m, 4m, and 7m does not form a valid triangle. In a triangle, the sum of the lengths of any two sides must be greater than the length of the third side according to the Triangle Inequality Theorem. In this case, 2m + 4m is less than 7m, violating the theorem. Therefore, a triangle with these side lengths cannot exist in Euclidean geometry.
There are 30 CM in 2m. I hope this answer's your question!
Assuming there is no waste, you will get exactly 10 lengths of rope all 2 metres long.
7/1.4 = 5 lengths.
They varied from 2m to 20m
32 posts
20 meters.2m/6sec = x/60secx = (2m*60sec)/6secx = 20m
The sequence "2m 10cm 2m 10cm 45cm 45cm" likely represents measurements, specifically lengths. It can be interpreted as two lengths of 2 meters and two lengths of 10 centimeters, along with two lengths of 45 centimeters. This could be useful in contexts like construction or design where specific dimensions are needed. Overall, the total length can also be calculated by converting all measurements to the same unit if necessary.
To determine how much cloth is wasted when cutting 18 dm from a 2m by 2m piece, we first convert the dimensions to the same unit. A 2m by 2m piece of cloth is equivalent to 200 dm by 200 dm, giving a total area of 40,000 dm². If 18 dm is cut from this piece, the area of the cut is 18 dm². Therefore, the waste can be calculated by subtracting the area cut from the total area, which would be 40,000 dm² - 18 dm² = 39,982 dm² of cloth remains, with only the 18 dm² cut being wasted.
32
It is: 200/8 = 25
20m
Eight 25 x 8 = 200 as 100 cm = 1 M
The triangle with side lengths of 2m, 4m, and 7m does not form a valid triangle. In a triangle, the sum of the lengths of any two sides must be greater than the length of the third side according to the Triangle Inequality Theorem. In this case, 2m + 4m is less than 7m, violating the theorem. Therefore, a triangle with these side lengths cannot exist in Euclidean geometry.