TEN of course !
7/1.4 = 5 lengths.
20 meters.2m/6sec = x/60secx = (2m*60sec)/6secx = 20m
It is: 200/8 = 25
The triangle with side lengths of 2m, 4m, and 7m does not form a valid triangle. In a triangle, the sum of the lengths of any two sides must be greater than the length of the third side according to the Triangle Inequality Theorem. In this case, 2m + 4m is less than 7m, violating the theorem. Therefore, a triangle with these side lengths cannot exist in Euclidean geometry.
There are 30 CM in 2m. I hope this answer's your question!
Assuming there is no waste, you will get exactly 10 lengths of rope all 2 metres long.
7/1.4 = 5 lengths.
They varied from 2m to 20m
32 posts
20 meters.2m/6sec = x/60secx = (2m*60sec)/6secx = 20m
To determine how much cloth is wasted when cutting 18 dm from a 2m by 2m piece, we first convert the dimensions to the same unit. A 2m by 2m piece of cloth is equivalent to 200 dm by 200 dm, giving a total area of 40,000 dm². If 18 dm is cut from this piece, the area of the cut is 18 dm². Therefore, the waste can be calculated by subtracting the area cut from the total area, which would be 40,000 dm² - 18 dm² = 39,982 dm² of cloth remains, with only the 18 dm² cut being wasted.
32
It is: 200/8 = 25
20m
Eight 25 x 8 = 200 as 100 cm = 1 M
The triangle with side lengths of 2m, 4m, and 7m does not form a valid triangle. In a triangle, the sum of the lengths of any two sides must be greater than the length of the third side according to the Triangle Inequality Theorem. In this case, 2m + 4m is less than 7m, violating the theorem. Therefore, a triangle with these side lengths cannot exist in Euclidean geometry.
Assuming that you are determining the surface area of a rectangle, in order to perform the calculation you would multiply the length (10m) by the width (2m):Surface Area = Length x WidthSurface Area = 10m x 2mSurface Area = 20m^2