The triangle with side lengths of 2m, 4m, and 7m does not form a valid triangle. In a triangle, the sum of the lengths of any two sides must be greater than the length of the third side according to the Triangle Inequality Theorem. In this case, 2m + 4m is less than 7m, violating the theorem. Therefore, a triangle with these side lengths cannot exist in Euclidean geometry.
To determine the number of triangles that can be formed with side lengths of 4m, 4m, and 7m, we can use the triangle inequality theorem. For a triangle to exist, the sum of the lengths of any two sides must be greater than the length of the third side. In this case, 4m + 4m = 8m, which is greater than 7m. Therefore, a triangle can be formed. Since all three sides are equal in length, this triangle is an equilateral triangle. So, there is only one triangle that can be formed with side lengths of 4m, 4m, and 7m.
9m - 28 = 2m Therefore, 7m = 28 m = 28/7 m = 4
7*8*4 = 224 cubic metres.
To find the area of a quadrilateral with sides of 7m, 4m, 5m, and 3m, you can use Brahmagupta's formula for the area of a cyclic quadrilateral: Area = √(s-a)(s-b)(s-c)(s-d), where s is the semiperimeter (s = (a + b + c + d) / 2) and a, b, c, and d are the lengths of the sides. Plug in the values of the sides into the formula to calculate the area.
7/1.4 = 5 lengths.
To determine the number of triangles that can be formed with side lengths of 4m, 4m, and 7m, we can use the triangle inequality theorem. For a triangle to exist, the sum of the lengths of any two sides must be greater than the length of the third side. In this case, 4m + 4m = 8m, which is greater than 7m. Therefore, a triangle can be formed. Since all three sides are equal in length, this triangle is an equilateral triangle. So, there is only one triangle that can be formed with side lengths of 4m, 4m, and 7m.
7m-2m = 5
A triangle doesn't have volume.
Every one of them could be a side of a rectangle. It is not possible to give an answer in respect of an unspecified rectangular object. however, i feel the question is incorrect as it should be sides of the triangle and according to it 3rd is the answer as 3+5<9 :)
5m-7m = 12 -2m = 12 -2m/-2 = 12/-2 m = -6
-(4m + 3)(5m - 2)
5m-12n
1m and 11m 2m and 10m 3m and 9m 4m and 8m 5m and 7m. The next one, 6m and 6m, would be a square.
4/7 - 4/m need a common denominator--multiply the first term by m/m and the second by 7/7 4m/7m - 28/7m (4m-28)/7m OR 4/7 - 4/m
I'm not sure what the question in the second part with the 2m 3m 4m etc. but the first part with the x y data points looks like a power curve approximately equal to:y = 0.77026 * x^(0.1968)
4m + 3m = 180 7m = 180 m = 25 5/7
9m - 28 = 2m Therefore, 7m = 28 m = 28/7 m = 4