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The triangle with side lengths of 2m, 4m, and 7m does not form a valid triangle. In a triangle, the sum of the lengths of any two sides must be greater than the length of the third side according to the Triangle Inequality Theorem. In this case, 2m + 4m is less than 7m, violating the theorem. Therefore, a triangle with these side lengths cannot exist in Euclidean geometry.
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How many triangles exist with the given side lengths 4m 4m 7m?
To determine the number of triangles that can be formed with side lengths of 4m, 4m, and 7m, we can use the triangle inequality theorem. For a triangle to exist, the sum of the lengths of any two sides must be greater than the length of the third side. In this case, 4m + 4m = 8m, which is greater than 7m. Therefore, a triangle can be formed. Since all three sides are equal in length, this triangle is an equilateral triangle. So, there is only one triangle that can be formed with side lengths of 4m, 4m, and 7m.
How do you find the area of 7m 4m 5m 3m?
To find the area of a quadrilateral with sides of 7m, 4m, 5m, and 3m, you can use Brahmagupta's formula for the area of a cyclic quadrilateral: Area = √(s-a)(s-b)(s-c)(s-d), where s is the semiperimeter (s = (a + b + c + d) / 2) and a, b, c, and d are the lengths of the sides. Plug in the values of the sides into the formula to calculate the area.
What is 9m-28 equals 2m?
9m - 28 = 2m Therefore, 7m = 28 m = 28/7 m = 4
What is the volume of a rectangle solid 7m by 8m by 4m?
7*8*4 = 224 cubic metres.
How many 1.4m lengths can be cut from 7m piece?
7/1.4 = 5 lengths.
