The triangle with side lengths of 2m, 4m, and 7m does not form a valid triangle. In a triangle, the sum of the lengths of any two sides must be greater than the length of the third side according to the Triangle Inequality Theorem. In this case, 2m + 4m is less than 7m, violating the theorem. Therefore, a triangle with these side lengths cannot exist in Euclidean geometry.
To determine the number of triangles that can be formed with side lengths of 4m, 4m, and 7m, we can use the triangle inequality theorem. For a triangle to exist, the sum of the lengths of any two sides must be greater than the length of the third side. In this case, 4m + 4m = 8m, which is greater than 7m. Therefore, a triangle can be formed. Since all three sides are equal in length, this triangle is an equilateral triangle. So, there is only one triangle that can be formed with side lengths of 4m, 4m, and 7m.
To find the area of a quadrilateral with sides of 7m, 4m, 5m, and 3m, you can use Brahmagupta's formula for the area of a cyclic quadrilateral: Area = √(s-a)(s-b)(s-c)(s-d), where s is the semiperimeter (s = (a + b + c + d) / 2) and a, b, c, and d are the lengths of the sides. Plug in the values of the sides into the formula to calculate the area.
9m - 28 = 2m Therefore, 7m = 28 m = 28/7 m = 4
7*8*4 = 224 cubic metres.
7/1.4 = 5 lengths.
To determine the number of triangles that can be formed with side lengths of 4m, 4m, and 7m, we can use the triangle inequality theorem. For a triangle to exist, the sum of the lengths of any two sides must be greater than the length of the third side. In this case, 4m + 4m = 8m, which is greater than 7m. Therefore, a triangle can be formed. Since all three sides are equal in length, this triangle is an equilateral triangle. So, there is only one triangle that can be formed with side lengths of 4m, 4m, and 7m.
The triangle with side lengths 4m, 4m, and 7m can exist because it satisfies the triangle inequality theorem. This theorem states that the sum of the lengths of any two sides must be greater than the length of the third side. In this case, 4m + 4m > 7m holds true. Therefore, only one triangle can be formed with these side lengths.
With side lengths of 4m, 4m, and 7m, only one triangle can be formed. This is an isosceles triangle, where two sides are equal (4m each) and the third side is different (7m). The triangle inequality theorem confirms that the sum of the lengths of any two sides must be greater than the length of the third side, which holds true in this case. Therefore, exactly one triangle exists with these lengths.
A triangle doesn't have volume.
7m-2m = 5
Every one of them could be a side of a rectangle. It is not possible to give an answer in respect of an unspecified rectangular object. however, i feel the question is incorrect as it should be sides of the triangle and according to it 3rd is the answer as 3+5<9 :)
To find the total displacement, we need to calculate the net movement in the north-south direction. The child walks 4m south and 5m south, totaling 9m south, and then walks 2m north and 5m north, totaling 7m north. The net displacement is 9m south - 7m north = 2m south. Therefore, the total displacement of the child is 2m south.
5m-7m = 12 -2m = 12 -2m/-2 = 12/-2 m = -6
To find the area of a quadrilateral with sides of 7m, 4m, 5m, and 3m, you can use Brahmagupta's formula for the area of a cyclic quadrilateral: Area = √(s-a)(s-b)(s-c)(s-d), where s is the semiperimeter (s = (a + b + c + d) / 2) and a, b, c, and d are the lengths of the sides. Plug in the values of the sides into the formula to calculate the area.
-(4m + 3)(5m - 2)
5m-12n
1m and 11m 2m and 10m 3m and 9m 4m and 8m 5m and 7m. The next one, 6m and 6m, would be a square.