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What is a 3 digit number divisible by 7 but not 2 the sum of your digits is 4?
I am a 3 digit number divisible by 7 but not 2 the sum of my digits is 4 what number am I
Is 650 divisable by 3?
No, because the sum of its digit is not divisible by 3
Is 5673 divisible by 3 or 9?
It is divisible by 3 but not divisible by 9. To test for divisibility by 3, sum the digits and if the sum is divisible by 3 then so is the original number; the test can be repeated ion the sum, so keep summing until a single digit remains and if this single digit is 3, 6 or 9, then the original number is divisible by 3: 5673 → 5 + 6 + 7 + 3 = 21 → 2 + 1 = 3 which is one of {3, 6, 9} so 5673 is divisible by 3. To test for divisibility by 9, sum the digits and if the sum is divisible by 9 then so is the original number; the test can be repeated ion the sum, so keep summing until a single digit remains(this single digit is known as the digital root of the number) and if this single digit is 9, then the original number is divisible by 9: 5673 → 5 + 6 + 7 + 3 = 21 → 2 + 1 = 3 which is not 9 so 5673 is not divisible by 9.
What is the divisibility of 3?
Add the digits of the number together and if the sum is divisible by 3 then the original number is divisible by 3. The test can be applied to the sum and so the summation can be repeated until a single digit remains; if this digit is 3, 6 or 9 then the original number is divisible by 3.
Is 501105 divisible by 2 3 5 9 10?
To determine if a number is divisible by another number, you need to check if the first number can be divided by the second number without leaving a remainder. For 501105: Divisibility by 2: A number is divisible by 2 if its last digit is even. The last digit of 501105 is 5, which is odd, so 501105 is not divisible by 2. Divisibility by 3: A number is divisible by 3 if the sum of its digits is divisible by 3. The sum of the digits of 501105 is 5+0+1+1+0+5=12, which is divisible by 3, so 501105 is divisible by 3. Divisibility by 5: A number is divisible by 5 if its last digit is 0 or 5. The last digit of 501105 is 5, so 501105 is divisible by 5. Divisibility by 9: A number is divisible by 9 if the sum of its digits is divisible by 9. The sum of the digits of 501105 is 12, which is not divisible by 9, so 501105 is not divisible by 9. Divisibility by 10: A number is divisible by 10 if its last digit is 0. The last digit of 501105 is 5, so 501105 is not divisible by 10.
What is a 3 digit number divisible by 7 but not 2 the sum of your digits is 4?
I am a 3 digit number divisible by 7 but not 2 the sum of my digits is 4 what number am I
Is 650 divisable by 3?
No, because the sum of its digit is not divisible by 3
What is the number n where if the sum of the digits of the number is divisible by n the number itself is divisible by n?
3 and 9. 93 has a digit sum of 12, initially, which is divisible by 3, but not by 9. So 93 is divisible by 3, but not by 9. 99 has a digit sum of 18, initially, which is divisible by 3 and 9. So 99 is divisible by both 3 and 9.
What is a 3 digit number that is divisible by 7 with a sum of 4?
301, if you mean that it's divisible by 7 and its DIGITS add up to 4
does 47904837 divisable by 3?
Yes, because the sum of its digit is divisible by 3
Is 5673 divisible by 3 or 9?
It is divisible by 3 but not divisible by 9. To test for divisibility by 3, sum the digits and if the sum is divisible by 3 then so is the original number; the test can be repeated ion the sum, so keep summing until a single digit remains and if this single digit is 3, 6 or 9, then the original number is divisible by 3: 5673 → 5 + 6 + 7 + 3 = 21 → 2 + 1 = 3 which is one of {3, 6, 9} so 5673 is divisible by 3. To test for divisibility by 9, sum the digits and if the sum is divisible by 9 then so is the original number; the test can be repeated ion the sum, so keep summing until a single digit remains(this single digit is known as the digital root of the number) and if this single digit is 9, then the original number is divisible by 9: 5673 → 5 + 6 + 7 + 3 = 21 → 2 + 1 = 3 which is not 9 so 5673 is not divisible by 9.
Is the number 26 divisible by 2 3 5 or 9 How do you know?
To be divisible by 2 the number must be even, that is its last digit must be 2, 4, 6, 8, or 0; the last digit of 26 is 6 which is one of {2, 4, 6, 8, 0} so 26 is even and divisible by 2. To be divisible by 3 sum the digits of the number; if this sum is divisible by 3 then the original number is divisible by 3. The test can be repeated on the sum until a single digit remains, in which case if this single digit is 3, 6, or 9 then the original number is divisible by 3; For 26: 2 + 6 = 8 which is not one of {3, 6, 9} so 26 is not divisible by 3. To be divisible by 5 the last digit must be a 0 or 5; the last digit of 26 is a 6 which is not 0 nor 5, so 26 is not divisible by 5. To be divisible by 9 sum the digits of the number; if this sum is divisible by 9 then the original number is divisible by 9. The test can be repeated on the sum until a single digit remains, in which case if this single digit is 9 then the original number is divisible by 9; For 26: 2 + 6 = 8 which is not 9 so 26 is not divisible by 9. 26 is divisible by 2 but not divisible by 3, 5 nor 9.
What is the divisibility of 3?
Add the digits of the number together and if the sum is divisible by 3 then the original number is divisible by 3. The test can be applied to the sum and so the summation can be repeated until a single digit remains; if this digit is 3, 6 or 9 then the original number is divisible by 3.
Is the number 432 divisible by 2 3 5 6 9 10?
To be divisible by 2 the number must be even, that is its last digit must be 2, 4, 6, 8, or 0; the last digit of 432 is 2 which is one of {2, 4, 6, 8, 0} so 432 is even and divisible by 2. To be divisible by 3 sum the digits of the number; if this sum is divisible by 3 then the original number is divisible by 3. The test can be repeated on the sum until a single digit remains, in which case if this single digit is 3, 6, or 9 then the original number is divisible by 3; For 432: 4 + 3 + 2 = 9 which is one of {3, 6, 9} so 432 is divisible by 3. To be divisible by 5 the last digit must be a 0 or 5; the last digit of 432 is a 2 which is not 0 nor 5, so 432 is not divisible by 5. To be divisible by 6, the number must be divisible by both 2 and 3; these have been tested above and found to be true, so 432 is divisible by 6. To be divisible by 9 sum the digits of the number; if this sum is divisible by 9 then the original number is divisible by 9. The test can be repeated on the sum until a single digit remains, in which case if this single digit is 9 then the original number is divisible by 9; For 432: 4 + 3 + 2 = 9 which is 9 so 432 is divisible by 9 To be divisible by 10 the last digit must be a 0; the last digit of 432 is a 2 which is not 0, so 432 is not divisible by 10. 432 is divisible by 2, 3, 6 and 9, but not divisible by 5 nor 10.
Is 341 divisible by 3?
No. To check divisibility by 3 add the digits together and if the sum is divisible by 3, then so is the original number. If the digits of the sum are summed and this is repeated until a single digit remains, then only if the digit is 3, 6 or 9 is the original number divisible by 3. 341 → 3 + 4 + 1 = 8 which is not divisible by 3 (not one of 3, 6 or 9), so 341 is not divisible by 3.
What is a 3 digit number the sum is 4 im divisible by 7 but not by 2?
721
Is 501105 divisible by 2 3 5 9 10?
To determine if a number is divisible by another number, you need to check if the first number can be divided by the second number without leaving a remainder. For 501105: Divisibility by 2: A number is divisible by 2 if its last digit is even. The last digit of 501105 is 5, which is odd, so 501105 is not divisible by 2. Divisibility by 3: A number is divisible by 3 if the sum of its digits is divisible by 3. The sum of the digits of 501105 is 5+0+1+1+0+5=12, which is divisible by 3, so 501105 is divisible by 3. Divisibility by 5: A number is divisible by 5 if its last digit is 0 or 5. The last digit of 501105 is 5, so 501105 is divisible by 5. Divisibility by 9: A number is divisible by 9 if the sum of its digits is divisible by 9. The sum of the digits of 501105 is 12, which is not divisible by 9, so 501105 is not divisible by 9. Divisibility by 10: A number is divisible by 10 if its last digit is 0. The last digit of 501105 is 5, so 501105 is not divisible by 10.
