The answer will depend on how many digits there are in each of the 30 numbers. If the 30 numbers are all 6-digit numbers then the answer is NONE!
If the 30 numbers are the first 30 counting numbers then there are
126 combinations of five 1-digit numbers,
1764 combinations of three 1-digit numbers and one 2-digit number, and
1710 combinations of one 1-digit number and two 2-digit numbers.
That makes a total of 3600 5-digit combinations.
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Starting at 12 and ending at 99, there are 30 two-digit numbers divisible by three.
Oh, isn't that a happy little question! To find the two-digit numbers divisible by 3, we start by finding the first two-digit number divisible by 3, which is 12. Then, we find the last two-digit number divisible by 3, which is 99. Now, we can count how many numbers there are between 12 and 99 that are divisible by 3.
The first 3 digit integer being a positive multiple of 30 is 120. The final 3 digit integer being a positive multiple of 30 is 990. 990 - 120 = 870. 870 ÷ 30 = 29 But, as 29 is the difference between the two limits and the limits themselves are included then there are 29 + 1 = 30 such numbers.
30.The first digit can be one of three digits {3, 6, 9} corresponding to the last digit being {1, 2, 3}, and for each of those three digits, the middle digit can be one of ten digits {0 - 9}, making 3 x 10 = 30 such numbers.It is assumed that a 3 digit number is a number in the range 100-999, excluding numbers starting with a leading zero, eg 090 is not considered a 3 digit number (though it would be a valid 3-digit number for a combination lock with 3 digits).
45 multiples of 2 plus 30 multiples of 3 minus 15 multiples of 6 equals 60 numbers