The answer will depend on how many digits there are in each of the 30 numbers. If the 30 numbers are all 6-digit numbers then the answer is NONE!
If the 30 numbers are the first 30 counting numbers then there are
126 combinations of five 1-digit numbers,
1764 combinations of three 1-digit numbers and one 2-digit number, and
1710 combinations of one 1-digit number and two 2-digit numbers.
That makes a total of 3600 5-digit combinations.
There are 30 such numbers.
Starting at 12 and ending at 99, there are 30 two-digit numbers divisible by three.
The first 3 digit integer being a positive multiple of 30 is 120. The final 3 digit integer being a positive multiple of 30 is 990. 990 - 120 = 870. 870 ÷ 30 = 29 But, as 29 is the difference between the two limits and the limits themselves are included then there are 29 + 1 = 30 such numbers.
30.The first digit can be one of three digits {3, 6, 9} corresponding to the last digit being {1, 2, 3}, and for each of those three digits, the middle digit can be one of ten digits {0 - 9}, making 3 x 10 = 30 such numbers.It is assumed that a 3 digit number is a number in the range 100-999, excluding numbers starting with a leading zero, eg 090 is not considered a 3 digit number (though it would be a valid 3-digit number for a combination lock with 3 digits).
There is no limitation given to the number of digits in the number, thus: For 3 digit numbers: to be less than 500 the first digit can be only one of {1, 2, 3, 4} leading to 4 × 5 × 4 = 80 numbers For 2 digit numbers: they are all less than 500, and there are 6 × 5 = 30 numbers For 1 digit numbers: they are all less than 500, and there are 6 numbers Thus there are in total 80 + 30 + 6 = 116 numbers that can be made form the digits {1, 2, 3, 4, 5 ,6} without repetitions that are less than 500.
There are 30 such numbers.
29 of them.
There are 300.
Starting at 12 and ending at 99, there are 30 two-digit numbers divisible by three.
30
30
30
30 of them.
If n is divisible by both 5 and 6, then it should be divisible by 30 (5 * 6). Considering you are asking for only two-digit numbers, the answer(s) would be 30, 60, and 90. So, three numbers.
300600900are some
13
The digit zeroes appear in the numbers 10, 20, 30, 40 and 50, making a total of 5 digit zeroes.