The answer will depend on how many digits there are in each of the 30 numbers. If the 30 numbers are all 6-digit numbers then the answer is NONE!
If the 30 numbers are the first 30 counting numbers then there are
126 combinations of five 1-digit numbers,
1764 combinations of three 1-digit numbers and one 2-digit number, and
1710 combinations of one 1-digit number and two 2-digit numbers.
That makes a total of 3600 5-digit combinations.
Starting at 12 and ending at 99, there are 30 two-digit numbers divisible by three.
Oh, isn't that a happy little question! To find the two-digit numbers divisible by 3, we start by finding the first two-digit number divisible by 3, which is 12. Then, we find the last two-digit number divisible by 3, which is 99. Now, we can count how many numbers there are between 12 and 99 that are divisible by 3.
The first 3 digit integer being a positive multiple of 30 is 120. The final 3 digit integer being a positive multiple of 30 is 990. 990 - 120 = 870. 870 ÷ 30 = 29 But, as 29 is the difference between the two limits and the limits themselves are included then there are 29 + 1 = 30 such numbers.
30.The first digit can be one of three digits {3, 6, 9} corresponding to the last digit being {1, 2, 3}, and for each of those three digits, the middle digit can be one of ten digits {0 - 9}, making 3 x 10 = 30 such numbers.It is assumed that a 3 digit number is a number in the range 100-999, excluding numbers starting with a leading zero, eg 090 is not considered a 3 digit number (though it would be a valid 3-digit number for a combination lock with 3 digits).
45 multiples of 2 plus 30 multiples of 3 minus 15 multiples of 6 equals 60 numbers
29 of them.
There are 300.
Starting at 12 and ending at 99, there are 30 two-digit numbers divisible by three.
To find the two-digit counting numbers less than 30, we consider the numbers from 10 to 29, which gives us 20 two-digit numbers. The multiples of 20 that are two-digit numbers are 20. Since 20 is already included in the count of two-digit numbers less than 30, the total remains 20. Therefore, there are 20 two-digit counting numbers that are either less than 30 or a multiple of 20.
30
30
Oh, isn't that a happy little question! To find the two-digit numbers divisible by 3, we start by finding the first two-digit number divisible by 3, which is 12. Then, we find the last two-digit number divisible by 3, which is 99. Now, we can count how many numbers there are between 12 and 99 that are divisible by 3.
30
30 of them.
If n is divisible by both 5 and 6, then it should be divisible by 30 (5 * 6). Considering you are asking for only two-digit numbers, the answer(s) would be 30, 60, and 90. So, three numbers.
300600900are some
13