First convert 1 lb of water to lb-moles which is 0.055 lb-moles (you'll need this later). This problem can be broken into 3 steps:
(1) You need to detemine how much heat is needed to raise room temperature water (68oF) to 212oF. This can be used using the heat capacity of water which at room temperature is 1 Btu/lboF. So the amount of heat needed for this is:
Q1 = m*Cp*ΔT
= (1 lb)*(1 Btu/lboF)*(212 - 68oF)
= 144 Btu
(2) Next you need to account for the phase change. The water changes to steam at 212oF. You use the heat of vaporization which you can look up in any Chemistry or Chemical Engineering Handbook. The Hvap that I found is 17493.5 Btu/lb-mole.
Q2 = n(lb-moles)*Hvap
= (0.055 lb-moles)*(17493.5 Btu/lb-mole)
= 972.64 Btu
(3) Next you need to find out how much heat is needed to raise the temperature of the steam from 212 to 213oF. You can look up the heat capacity of steam at 212oF to be 0.485 Btu/lboF.
Q3 = m*Cp*ΔT
= (1 lb)*(0.485 Btu/lboF)*(213-212oF)
= 0.485 Btu
To find the total heat needed add Q1+Q2+Q3 (144+972.64+0.485) =
1117.12 Btu
25
144
160 btu's. It takes 1 btu (British Thermal Unit) to change the temperature of 1lb of water 1°. This is referred to as sensible heat. This 1 to 1 ratio does not hold true when changing the state of that water to ice or to steam. Changing the state 1lb of water at 212° to 1lb of steam at 212° you must add 970 btu's and to change 1lb of water at 32° into 1lb of ice at 32° you must add 144 btu's. This is referred to as latent heat.
If you're in Celsius, 13459.5 Btu's. If you're in Fahrenheit, 12632.5 Btu's.
100 BTU if it's Fahrenheit
One BTU is the energy required to raise one pound of water by one degrees. Therefore, your answer would be one half.
Heat. Ice, solid water, at 32 degrees F needs 144 btus of heat per pound to liquify completely. Water at 212F needs 970.3 btus per pound to evaporate completely into dry steam. Water vapor (visible steam), in air, {say from a pot} is actually about 3 to 10% dry steam and only required about 28 to 100 btus per pound to vaporize and become airborne, This is an odd characteristic of water, that varying proportions of dry steam will carry large amounts of liquid water along with it as it evaporates (Wet Steam).Water can exist in all three states at the same time, in the same general vicinity. Ice floats on liquid water and the air around it will also contain some amount of water vapor (humidity).
From high school science class; it takes 144 BTUs to melt a pound of ice. That takes it to 32 degrees F. To then raise the temp to 72 deg., would take about 40 more BTUs.
1)This is a 5 part question. The first is realizing that 20F to 32F uses .5BTU per pound per degree. That means it takes 32-20=12*.5=6BTUs to get the ice to 32F. 2)Then you need to know the Latent Heat of Fusion for Ice which is 144BTUs (given). Lets assumes the ice changes from ice to water instantaneously at 32F. 3)Next we calculate the BTUs from 32F to 212F. Which is 1BTU per pound per degree F. 212-32=180 so it take 180BTUS. 4)Next we have to use the Latent Heat of Vaporization of water which will say instantaneously converts water to vapor. This takes 970BTUS (given). 5)Then we calculate the BTUS from 212F to 220F. Which is .5BTUs per pound per degree F which is 220-212=8*.5=4BTUs...... Finally add up all the BTUs and you get 6+144+180+970+4=1304BTUs.
BTUs to Evaporate One Pound of WaterQuick Answer: Somewhere around 1000BTU/lb Long answer: It depends on the temperature of the water you start with. Before you can evaporate the water, you must heat it to it's boiling point. The warmer the water you start with the fewer BTUs will be needed to heat the water to its boiling point. Keep in mind the BTUs require to raise the water to its boiling point are very few compared to the BTUs required to change the water from a liquid to a gas.One pound of steam contains 1150 BTUs. This is the energy you need to put into the water for it to evaporate if you start with water at 32F. If you start with water at 100F the water already has 70 BTU/lb so the BTUs required to evaporate the water when you start at 100F is 1150-70 = 1080 BTU and so on.You can get all this information in a steam table which can be found easily by searching the web.
1320 btu`s
There are no BTUs in an office water-cooler. But you can calculate how many BTUs are removed by the cooler. One BTU or British Thermal Unit is the amount of heat energy required to raise the temperature of one pound of water one degree Fahrenheit. There for when you remove one BTU you are lowering one pound of water one degree Fahrenheit. So if you know how many pounds of water you have and the temperature of the water you start with and the temperature of the water comming out of the cooler you can calculate how many BTUs the cooling unit of the water cooler has removed. BTU=Temp1 - Temp 2 X LB water
25
2250
A 100 pound propane tank has a capacity of 2,160,509 BTUs
That will completely depend on how much water there is.
Well, you seem like a very smart kid. Let me ask you something: if you had one pound of naiveness in one hand and one pound of idiocy in the other, which one weighs more? Let me tell you a secret: Its the same!