You Could Only Do It Ten (10) Combination :) :D
9 of them because 9/9 = 1
Do you mean "How many ways can you arrange the digits '6', '9', '1', and '3' " ??If so, then the answer is 24 ways.There is only one combination, since the order of the digits in a combination does not matter. If the order does matter, then they are called permutations and there are 24 of them.
18 / (1/9) = 18 * (9/1) = 162
9
9 times 9 times 9 times 9 times 9 times 9 times 9 times 9 times 9 = Imagine it's a combination lock with 9 tumblers. Each tumbler has 9 "positions" - the digits from 1 to 9. So you multiply the number of digits [9] against itself [9] for as many tumblers are in the combination (9). Tumbler # 1 2 3 4 5 6 7 8 9 Number of possible digits 9 9 9 9 9 9 9 9 9
You Could Only Do It Ten (10) Combination :) :D
If a digit can repeat in the same combination, there are (9 x 9 x 9 x 9 x 9) = 59,049 .If all 5 digits in a combination must be different, there are (9 x 8 x 7 x 6 x 5) = 15,120 .
9 of them because 9/9 = 1
277612920, but only if any number (including 9) can appear more than once.
81
9 / (1/4) = 9*4/1 = 36 of them.
If the digit 0 is allowed then the answer is 1/(10*9*8) = 1/720 = 0.0014 approx. If 0 is disallowed, then 1/(9*8*7) = 1/504 = 0.0020 approx.
1 5/9
it is a combination: 9!/4!=9 x 8 x 7 x 6
18 / (1/9) = 18 * (9/1) = 162
Do you mean "How many ways can you arrange the digits '6', '9', '1', and '3' " ??If so, then the answer is 24 ways.There is only one combination, since the order of the digits in a combination does not matter. If the order does matter, then they are called permutations and there are 24 of them.