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9 of them because 9/9 = 1
You Could Only Do It Ten (10) Combination :) :D
18 / (1/9) = 18 * (9/1) = 162
C(8+1, 1)= c(9, 1) = [9!/1!(9-1)!] = [9!/1! 8!] = [9/1!] = 9.
Do you mean "How many ways can you arrange the digits '6', '9', '1', and '3' " ??If so, then the answer is 24 ways.There is only one combination, since the order of the digits in a combination does not matter. If the order does matter, then they are called permutations and there are 24 of them.