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9 times 9 times 9 times 9 times 9 times 9 times 9 times 9 times 9 =

Imagine it's a combination lock with 9 tumblers. Each tumbler has 9 "positions" - the digits from 1 to 9. So you multiply the number of digits [9] against itself [9] for as many tumblers are in the combination (9).

Tumbler # 1 2 3 4 5 6 7 8 9

Number of

possible

digits 9 9 9 9 9 9 9 9 9

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16y ago

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Related Questions

If using 7 single digit numbers how many different combinations can you get?

Number of 7 digit combinations out of the 10 one-digit numbers = 120.


How many 10 digit combinations are there for the numbers 0 through 9?

Exactly 3,628,800, or 10!.


How many 5 digit combos in 30 numbers?

The answer will depend on how many digits there are in each of the 30 numbers. If the 30 numbers are all 6-digit numbers then the answer is NONE! If the 30 numbers are the first 30 counting numbers then there are 126 combinations of five 1-digit numbers, 1764 combinations of three 1-digit numbers and one 2-digit number, and 1710 combinations of one 1-digit number and two 2-digit numbers. That makes a total of 3600 5-digit combinations.


If using numbers 1 through 8 how many different 4 digit combinations can be made?

15


If using numbers 1 through 4 how many different 4 digit combinations can be made?

10,000


How many 7 digit combinations can be made using the numbers 1 through 9?

It is: 9C7 = 36


How many 7 digit combinations can you have if you can only use the numbers 0 through 9 once each?

10!/3! = 604800 different combinations.


How many 7 digit combinations are there for numbers 1 through 9?

that would be 9 to the 7th power i believe.


How many different 3 digit combinations can be made using numbers one through nine?

Through the magic of perms and coms the answer is 729


How many 4 digit combanations using the numbers 1-7?

There are 840 4-digit combinations without repeating any digit in the combinations.


If using numbers 0 through 9 how many different 2 digit combinations can be made?

If there are no restrictions on duplicated numbers or other patterns of numbers then there are 10 ways of selecting the first digit and also 10 ways of selecting the second digit. The number of combinations is therefore 10 x 10 = 100.


How many 3 digit combinations numbers one through nine?

9!/6!, if the six different orders of any 3 digits are considered distinct combinations.

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