If you pick at random five numbers out of a pool of fifty-six numbers, where each number can only appear once, there are
56 X 55 X 54 X 53 X 52 =
different ways of putting them together.
If the order the numbers appear doesn't matter (eg if 1, 8, 20, 45, 51 is considered the same as 45, 8, 1, 20, 51) then you need to divide this number by
5 X 4 X 3 X 2 X 1 =
/
=
56 combinations. :)
Number of combinations = 59*58*57*56*55/(5*4*3*2*1) = 5006386.
Did you write the question right? Because this is not possible Work: 56/2 = 28 It can not be 27 and 28, or 28 and 29 7 x 8 = 56
7 * 8 = 56 1 * 56 = 56
To get an average, add the numbers together and divide by how many numbers there are.... 33 + 34 + 78 + 56 = 201. 201 / 4 = 50.25
Assuming 9 numbers chosen from 56, with no repetition allowed, there are 7575968400 possible combinations.
There are many possible answers. 1 and 56, for example.
56!/5!51! = 3819816
56 combinations. :)
There are multiple possible two numbers whose LCM is 56: 1 & 56 2 & 56 4 & 56 7 & 8 7 & 56 8 & 14 8 & 28 8 & 56 14 & 56 28 & 56 56 & 56
Number of combinations = 59*58*57*56*55/(5*4*3*2*1) = 5006386.
Two of them.
1,2,4,7,8,14,28,56
8C3 = 56 of them
56 and 112, among many others.
1 (this is a factor of all numbers) and 2 (since 54 and 56 are both even numbers)
1 (this is a factor of all numbers) and 2 (since 54 and 56 are both even numbers) This is it.