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To calculate the number of combinations for splitting 10 into 3 groups with no less than 2 in a group, we can use a mathematical concept known as stars and bars. In this case, we are essentially distributing 10 identical items (stars) into 3 distinct groups (bars). The formula for this scenario is (n+k-1) choose (k-1), where n is the total number of items (10) and k is the number of groups (3). Plugging in the values, we get (10+3-1) choose (3-1) = 12 choose 2 = 66 combinations.
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Is 34 an abundant perfect or a deficient number?
To find out if a number is abundant, perfect or deficient, you first need to split it into its prime factors: 34 = 2x17 The next step would be to find any combinations, but as we have only 2 prime factors, those are the two we'll work with. You add these together, with 1, and get 20. When this sums to less than the original number it's a deficient number. 20 is less than 34, and so 34 is a deficient number.
How is 0.25 less then 2 fifths?
if you split it in five parts then you have three and a half on each side but 0.25 you dont have a whole you have 100 ths
Chloe has to divide 600 jellybeans into groups that are less than 100 but more than 10. What are three possible groupings?
25
How many 5-number combinations can you make from 9 numbers?
-4
How big can a remainder be?
AnswerFor a division problem between two whole numbers, A remainder can be any whole number that is less than the divisor. If the remainder is equal to the divisor, then the quotient is not large enough. Think of this problem: how many times will 3 go into 10. So you can have 3 groups of 3, with 1 left over (the remainder). If you chose to have only 2 groups of 3, then there will be 6 with 4 left over. Clearly you can make one more group of 3 from the 4, and have 1 left over.
