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In combinatorial terms it makes no difference whether you pick one chairperson out of 12 and five other persons, or you pick 6 persons out of 12 and then they pick one of their subgroup to be chair.

Number of ways of selecting 1 out of 12 = 12

That leaves 11 persons and you want 5 from them. this can be done in 11C5 = 11*10*9*8*7/(5*4*3*2*1) = 452 ways.

So total number of ways = 12*462 = 5544

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Q: How many committee of 5 persons with a chairperson can be selected from 12 persons?
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