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There are 3 different answers because of the leap years. this is 7 years with 2 leap years: If the beginning year is a leap year, when the leap year is next year, or the leap year is two years after the beginning year, there will be two leap years in the seven year period, and so the number of days will be 2557. If the beginning year isn't in any of the above catergories, there will only be 2556 days, because of only one leap year. If the beginning year is 3 years before a year that is a multiple of 100, but not a multiple of 400, there will be no leap years. For example, the 7 year period beginning in 2097 has no leap years because 2100 is not a leap year. In that case there will be 365 * 7 = 2555 days.
To calculate the number of days in 12 years, we need to consider leap years. In a 12-year period, there will be 3 leap years (years divisible by 4), which have 366 days each. The remaining 9 years will have 365 days each. So, the total number of days in 12 years can be calculated as: (3 * 366) + (9 * 365) = 1092 + 3285 = 4377 days.
In any given stretch of four years, there are three normal years and one leap year. Therefore, 4 years is equal to (365 x 3) + 366 = 1461 days.
Thursday Total 30 years. 22 non-leap,8 leap years=38 odd days. 3 odd days.
You will have to figure out how many leap years. In this answer, I figured it based on if the leap year was on the 1st year. Then you would have one in your 1st, 5th and 9th year. Also figured that a year is 365 days and a leap year is 366 days. There are 31,536,000 sec in a year and 31, 622,400 sec in a leap year. 365dys x 24 hrs = 8760hrs a year 366dys x 24 hrs = 8784 hrs a leap yr 8760hrs x 60min=525,600min/yr 8,784hrs x 60min=527,040min/lp yr 525,600mins x 60sec=31,536,000sec/yr 527,040min x 60sec=31,622,400 sec/lpyr 31,536,000 x 8 regular years =252,288,000secs in 8 regular years 31,622,400 x 3 leap years = 94,867,200sec in 3 leap year 252,288,000sec +94,867,200sec = 347155200 347,155,200secs in 11 years if there are 3 leap years