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How many two digit numbers can you form using the digits 1235679 with repetition allowed?
You have seven different digits (symbols) to choose from, so you can form seven different one digit numbers and 7×7=72=49 different two digit numbers.
How many 3-digit numbers can be formed using the digits 0 2 3 without repetition?
# 230 # 203 # 320 # 302
How many seven digit numbers are there when 0 and 4 cannot be the leading number?
If the number can contain repeated digits, the answer is 800000. Without repetition, there are 483840.
How many 4-digit numbers can be formed using the digits 1 2 3 4 5 6 7 8 and 9?
With repetition, 94 = 6561. Without repetition, 9*8*7*6 = 3024.
How many different ways can a license plate be made containing two letters and three digits with repetition of the numbers and letters not allowed?
There are 676,000 ways to make the license plates.
How many 4 digit numbers can be formed from digits 123456789?
5040 different 4 digit numbers can be formed with the digits 123456789. This is assuming that no digits are repeated with each combination.
How many different two digit numbers can you form using the digits 1 2 5 7 8 and 9 with repetition?
30 without repetition (6P2) 66 with repetition (12C2)
How many numbers can be formed using the digits 37 and 9 without repetition?
15 of them.
How many three digit numbers can be formed using the digits 873 and 6 without repetition?
I take it that you want to make three digits numbers with 8,7,3, and 6 without repetition. The first digit cane be selected from among 4 digits, the second from 3 digits, the third digit from 2, hence the number of three digit numbers that can be formed without repetition is 4 x 3 x 2 = 24
How many four digits numbers can be made with 1 4 5 9 without repetition?
To calculate the number of four-digit numbers that can be made using the digits 1, 4, 5, and 9 without repetition, we use the permutation formula. Since there are 4 digits to choose from for the first digit, 3 for the second, 2 for the third, and 1 for the fourth, the total number of permutations is 4 x 3 x 2 x 1 = 24. Therefore, there are 24 different four-digit numbers that can be formed using the digits 1, 4, 5, and 9 without repetition.
How many 3-digit numbers can be formed by the digits 4 5 9 without repetition?
Six (6)
How many 5 digit numbers can be made using the digits 12679 if repetition isn't allowed?
To form a 5-digit number using the digits 1, 2, 6, 7, and 9 without repetition, we can use all five digits. The number of different arrangements of these 5 digits is calculated by finding the factorial of the number of digits, which is 5!. Therefore, the total number of 5-digit numbers that can be formed is 5! = 120.
How many different numbers can you form using all four numbers of 1 9 8 4?
The four digits can be used to produce infinitely many different numbers if repetition is permitted. Without repetition, there are 24 possible numbers. A lot more can be produced if the numbers are combined using binary oprations, fore example, 19 * 8/4 = 19*2 = 38.
Where d represents a digit from 0 9 how many different ISBN numbers are possible if repetition of digits is allowed?
There are 10 to the 10th power possibilities of ISBN numbers if d represents a digit from 0 to 9 and repetition of digits are allowed. That means there are 10,000,000,000 ISBN numbers possible.
How many two digit numbers can you form using the digits 1235679 with repetition allowed?
You have seven different digits (symbols) to choose from, so you can form seven different one digit numbers and 7×7=72=49 different two digit numbers.
How many 3 digit numbers can be formed using the digits 1 to 9 without repetition?
9*8*7 = 504 of them.
How many 3 digit numbers can be formed by the digits 4 5 9 without repetition?
3*2*1 = 6 of them.
