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36 two digit numbers can be formed...(:

From Rafaelrz: The question can be stated as;

how many permutations of two different digits can be

obtained from a set of six different digits ?

Answer:

nPr equals n!/(n-r) ...... for n = 6, r = 2

6P2 equals 6!/(6-2)! equals 30 Permutations.

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โˆ™ 2011-11-10 07:20:46
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A polynomial of degree zero is a constant term

The grouping method of factoring can still be used when only some of the terms share a common factor A True B False

The sum or difference of p and q is the of the x-term in the trinomial

A number a power of a variable or a product of the two is a monomial while a polynomial is the of monomials

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Q: How many different two digit numbers can you form using the digits 1 2 5 7 8 and 9 without repetition?
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