0
36 two digit numbers can be formed...(:
From Rafaelrz: The question can be stated as;
how many permutations of two different digits can be
obtained from a set of six different digits ?
Answer:
nPr equals n!/(n-r) ...... for n = 6, r = 2
6P2 equals 6!/(6-2)! equals 30 Permutations.
Add your answer:
Earn +20 pts
How many different two digit numbers can you form using the digits 1 2 5 7 8 and 9 with repetition?
30 without repetition (6P2) 66 with repetition (12C2)
How many numbers can be formed using the digits 37 and 9 without repetition?
15 of them.
How many three digit numbers can be formed using the digits 873 and 6 without repetition?
I take it that you want to make three digits numbers with 8,7,3, and 6 without repetition. The first digit cane be selected from among 4 digits, the second from 3 digits, the third digit from 2, hence the number of three digit numbers that can be formed without repetition is 4 x 3 x 2 = 24
How many four digits numbers can be made with 1 4 5 9 without repetition?
24
How many 3-digit numbers can be formed by the digits 4 5 9 without repetition?
Six (6)
Where d represents a digit from 0 9 how many different ISBN numbers are possible if repetition of digits is allowed?
There are 10 to the 10th power possibilities of ISBN numbers if d represents a digit from 0 to 9 and repetition of digits are allowed. That means there are 10,000,000,000 ISBN numbers possible.
How many different numbers can you form using all four numbers of 1 9 8 4?
The four digits can be used to produce infinitely many different numbers if repetition is permitted. Without repetition, there are 24 possible numbers. A lot more can be produced if the numbers are combined using binary oprations, fore example, 19 * 8/4 = 19*2 = 38.
How many two digit numbers can you form using the digits 1235679 with repetition allowed?
You have seven different digits (symbols) to choose from, so you can form seven different one digit numbers and 7×7=72=49 different two digit numbers.
How many 3 digit numbers can be formed using the digits 1 to 9 without repetition?
9*8*7 = 504 of them.
How many 3 digit numbers can be formed by the digits 4 5 9 without repetition?
3*2*1 = 6 of them.
How many 3 digit numbers are possible from the digits 012345?
Assuming that the first digit can't be zero: If repetition of digits is permitted: (5 x 6 x 6) = 180 numbers of 3 digits. If repetition of digits is not permitted: (5 x 5 x 4) = 100 numbers of 3 digits.
How many 4 digit numbers can be made to give the sum of 6?
If repetition of digits is allowed, then 56 can.If repetition of digits is not allowed, then only 18 can.
Subjects
Math Science History Arts & Humanities Social Studies Engineering & Technology Business OtherTop Categories
Algebra Chemistry Biology World History English Language Arts Psychology Computer Science EconomicsProduct
Community Guidelines Honor Code Mobile App Answers+ Flashcard Maker Study Guides Math Solver FAQGet the Answers App
