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I have my own formula for this. We, together with my friend Gio made an investigative report concerning this. The formula that we got is (2n-1 - 1), where n is the number we are looking for how many addends it has. Let's try. If n is 1: its addends are o. There's no two or more numbers that we can add to get a sum of 1 (excluding 0). Let's try a higher number. Let's try 4. 4 has addends: 1+1+1+1, 1+2+1, 1+1+2, 2+1+1, 1+3, 2+2, 3+1. Its total is 7. Let's check with the formula. 24-1 = 23 - 1= 8-1=7.

Let's try 15. 215-1=14 - 1 = 16384 - 1 = 16383. Therefore, there are 16383 ways to add numbers that will equal to 15.

(Note: Addends are positive numbers only.)

(You can try other numbers, to check whether our formula is correct or not.)

In subtraction, it's infinite. Since, we can assume 45-30, 12345-12330, ...and so on and so far. That's why it's infinite.

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Q: How many different ways can you add and subtract whole numbers numbers to equal 15?
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