Chen has 8 nickels, 2 dimes, and 6 quarters.
1 quarter and 21 dimes or 3 quarters and 16 dimes or 5 quarters and 11 dimes or 7 quarters and 6 dimes or 9 quarters and 1 dime
If you want only quarters, divide 6 / 0.25. [24 quarters, 0 dimes] If you want only dimes, divide 6 / 0.1. [60 dimes, 0 quarters] If you want some combination of quarters and dimes, you can experiment a bit. For this specific problem, you'll need an even number of quarters to get the exact amount - so you can use zero quarters, 2 quarters, 4 quarters, etc.
You can have 0, 2, 4, 6, or 8 quarters. The remaining amount is in dimes.
12 quarters and 6 dimes 2(.25x) + .10x = 3.60 50x + 10x = 360 60x = 360 x = 6
Chen has 8 nickels, 2 dimes, and 6 quarters.
3 quarters, 2 dimes and a nickel
1 quarter and 21 dimes or 3 quarters and 16 dimes or 5 quarters and 11 dimes or 7 quarters and 6 dimes or 9 quarters and 1 dime
If you want only quarters, divide 6 / 0.25. [24 quarters, 0 dimes] If you want only dimes, divide 6 / 0.1. [60 dimes, 0 quarters] If you want some combination of quarters and dimes, you can experiment a bit. For this specific problem, you'll need an even number of quarters to get the exact amount - so you can use zero quarters, 2 quarters, 4 quarters, etc.
Three quarters, two dimes, one nickel
12 quarters 6 dimes
You can have 0, 2, 4, 6, or 8 quarters. The remaining amount is in dimes.
Peggy had three times as many quarters as nickels. She had $1.60 in all. How many nickels and how many quarters did she have?
To make $2.50 from quarters (worth 25 cents) and dimes (worth 10 cents), we can set up a system of equations. Let q represent the number of quarters and d represent the number of dimes. The equations would be 25q + 10d = 250 (representing the total value in cents) and q + d = 25 (representing the total number of coins). Solving these equations simultaneously, we find that there are 6 ways to make $2.50 using quarters and dimes.
$4.54
12 quarters and 6 dimes 2(.25x) + .10x = 3.60 50x + 10x = 360 60x = 360 x = 6
The man has 13 dimes and 7 quarters, which equate to $3.05 $1.30 + $1.75 If he had 13 quarters and 7 dimes he would have $3.95 $3.25 + 70c The method used to work this out was dividing 90c by the difference between the value of a dime and a quarter- i.e. 15c . 90 / 15 = 6, so of 20 coins, 6 more were dimes than quarters. Subtract 6 from 20, then halve the result = 7 the lower number is 7, the higher number is 7+6, = 13. Please also note that 'Quarters' is spelled with 2 'r's