If you want only quarters, divide 6 / 0.25. [24 quarters, 0 dimes]
If you want only dimes, divide 6 / 0.1. [60 dimes, 0 quarters]
If you want some combination of quarters and dimes, you can experiment a bit. For this specific problem, you'll need an even number of quarters to get the exact amount - so you can use zero quarters, 2 quarters, 4 quarters, etc.
Chen has 8 nickels, 2 dimes, and 6 quarters.
1 quarter and 21 dimes or 3 quarters and 16 dimes or 5 quarters and 11 dimes or 7 quarters and 6 dimes or 9 quarters and 1 dime
15 dimes equals 6 quarters.
12 quarters and 6 dimes 2(.25x) + .10x = 3.60 50x + 10x = 360 60x = 360 x = 6
20 ways:3 quarters, 2 dimes, 1 nickel3 quarters, 2 dimes, 5 pennies3 quarters, 1 dime, 3 nickels3 quarters, 1 dime, 2 nickels, 5 pennies3 quarters, 5 nickels3 quarters, 4 nickels, 5 pennies2 quarters, 5 dimes2 quarters, 4 dimes, 2 nickels2 quarters, 4 dimes, 1 nickel, 5 pennies2 quarters, 3 dimes, 4 nickels2 quarters, 3 dimes, 3 nickels, 5 pennies1 quarter, 7 dimes, 1 nickel1 quarter, 7 dimes, 5 pennies1 quarter, 6 dimes, 3 nickels1 quarter, 6 dimes, 2 nickels, 5 pennies1 quarter, 5 dimes, 5 nickels1 quarter, 5 dimes, 4 nickels, 5 pennies8 dimes, 4 nickels8 dimes, 3 nickels, 5 pennies7 dimes, 5 nickels, 5 pennies
12 quarters 6 dimes
5 dimes,6 nickles.8 dimes
Chen has 8 nickels, 2 dimes, and 6 quarters.
1 quarter and 21 dimes or 3 quarters and 16 dimes or 5 quarters and 11 dimes or 7 quarters and 6 dimes or 9 quarters and 1 dime
15 dimes equals 6 quarters.
To make $2.00 using quarters (worth $0.25) and dimes (worth $0.10), we can set up a system of equations. Let q represent the number of quarters and d represent the number of dimes. The equation would be 0.25q + 0.10d = 2.00. To solve this equation, we can use substitution or elimination methods. The possible combinations of quarters and dimes to make $2.00 are (q=6, d=0), (q=1, d=15), and (q=11, d=5).
Peggy had three times as many quarters as nickels. She had $1.60 in all. How many nickels and how many quarters did she have?
60
(6 * 25) + (4 * 10) + (10 * 5) = 150 + 40 + 50 = 240 cents = 2.40 dollars
12 quarters and 6 dimes 2(.25x) + .10x = 3.60 50x + 10x = 360 60x = 360 x = 6
1)4 quarters 2)2 half dollars 3)10 dimes 4)20 nickels 5)half dollar 2 quarters 6)half dollar 5 dimes 7)half dollar 10 nickels 8)half dollar 4 dimes 2 nickels 9)half dollar 4 nickels 3 dimes 10)half dollar 2 nickels 4 dimes 11)half dollar 6 nickels 2 dimes 12)half dollar 8 nickels 1 dime 13)3 quarters 2 dimes 1 nickel 14)2 quarters 5 dimes 15)2 quarters 10 nickels 16)2 quarters 4 nickels 3 dimes 17)2 quarters 2 nickels 4 dimes 18)2 quarters 6 nickels 2 dimes 19)2 quarters 8 nickels 1 dime 20)1 quarter 6 dimes 3 nickels 21)1 quarter 7 dimes 1 nickel 22)1 quarter 5 dimes 5 nickels 23)1 quarter 4 dimes 2 nickels 24)1 quarter 3 dimes 4 nickels 25)1 quarter 2 dimes 6 nickels 26)1 quarter 1 dime 13 nickels 27)5 dimes 10 nickels 28)4 dimes 12 nickels 29)3 dimes 14 nickels 30)2 dimes 16 nickels 31)1 dime 18 nickels 32)6 dimes 8 nickels 33/7 dimes 6 nickels 34)8 dimes 4 nickels 35)9 dimes 2 nickels
The man has 13 dimes and 7 quarters, which equate to $3.05 $1.30 + $1.75 If he had 13 quarters and 7 dimes he would have $3.95 $3.25 + 70c The method used to work this out was dividing 90c by the difference between the value of a dime and a quarter- i.e. 15c . 90 / 15 = 6, so of 20 coins, 6 more were dimes than quarters. Subtract 6 from 20, then halve the result = 7 the lower number is 7, the higher number is 7+6, = 13. Please also note that 'Quarters' is spelled with 2 'r's