answersLogoWhite

0

median = 100, mean = 1000

set of numbers = {a,b,100,c,d}

a+b+100+c+d = 5000

As the set contains distinct numbers, and there is no range that is given in the problem, we can consider the set of numbers as {1,2,100,101,4796}

So the largest possible integer can be 4796.

User Avatar

Wiki User

13y ago

What else can I help you with?

Related Questions

Set of all positive integers less than 6?

1, 2, 3, 4 and 50 should also be included..


The sum of five different positive integers is 500 The largest possible value for one of these integers is?

490.


What are the 3 kinds of integers?

Negative, Zero and Positive is one possible classification.


What are the rules in dividing integers?

A positive integer divided by a positive integer always results in a positive quotient. It is not possible to divide by zero.


9 squared belongs to what family of real numbers?

At least the following families: all integers; all positive integers; all odd integers; and all "square integers", that is, integers that are squares of other integers.


What 3 positive integers multiplied equal 47?

{1,1,47} is the only possible set.


Is the sum of two integers always positive?

No. The answer depends on the context in terms of which the numbers are considered to be opposite.


What ia the smallest possible sum of 2 positive integers whose product is 36?

12


Can the sum of the first n consecutive positive integers be equal to the square of a prime number?

No, it is not possible.


What are The product of two consecutive positive integers is 27 more than five times the larger integer. Find the integers?

One possible answer is -4 and -3.


How many samples of size 5 are possible when selecting from a set of 10 distinct integers if the sampling is done with replacement?

105 or 100,000


How many positive integers less than 1000 have distinct digits and are even?

To determine the number of positive integers less than 1000 with distinct digits and are even, we need to consider the possible combinations of digits. Since the number must be even, the last digit must be even, giving us 5 options (0, 2, 4, 6, 8). For the hundreds digit, we have 9 options (1-9), and for the tens digit, we have 8 options (0-9 excluding the hundreds digit and the last digit). Therefore, the total number of such integers is 5 * 9 * 8 = 360.