median = 100, mean = 1000
set of numbers = {a,b,100,c,d}
a+b+100+c+d = 5000
As the set contains distinct numbers, and there is no range that is given in the problem, we can consider the set of numbers as {1,2,100,101,4796}
So the largest possible integer can be 4796.
1, 2, 3, 4 and 50 should also be included..
490.
No. The answer depends on the context in terms of which the numbers are considered to be opposite.
well, the square root of 24999999 is 4999.999, and the answer is 4999 • 5001. Hope this helps!
Unless you're talking about the integers... in which case the answer is that 1 and -1 are equally close to zero... there's no such thing, not even if you limit yourself to only rational numbers. There is a smallest possible positive value distinct from zero that can be represented in a computer, but what it is depends on the details of how the computer was constructed.
1, 2, 3, 4 and 50 should also be included..
490.
Negative, Zero and Positive is one possible classification.
A positive integer divided by a positive integer always results in a positive quotient. It is not possible to divide by zero.
At least the following families: all integers; all positive integers; all odd integers; and all "square integers", that is, integers that are squares of other integers.
{1,1,47} is the only possible set.
No. The answer depends on the context in terms of which the numbers are considered to be opposite.
12
No, it is not possible.
One possible answer is -4 and -3.
105 or 100,000
To determine the number of positive integers less than 1000 with distinct digits and are even, we need to consider the possible combinations of digits. Since the number must be even, the last digit must be even, giving us 5 options (0, 2, 4, 6, 8). For the hundreds digit, we have 9 options (1-9), and for the tens digit, we have 8 options (0-9 excluding the hundreds digit and the last digit). Therefore, the total number of such integers is 5 * 9 * 8 = 360.