6
Assuming all faces need to be painted, the question can be written as "how many faces on 43 cubes." There are 6 faces on each cube. Thus the answer can be got from the multiplication 43x6. Doing this gives us 258, so the number of faces that would need to be painted is 258.
It depends on how they are connected, i.e. how many are connected to each other. If they are connected in a line, with just one connection between any two cubes, the rectangle formed still has 6 faces, four of them rectangular (10 of the original 36 cubic faces are hidden between cubes, leaving 26 showing). If the maximum number of faces are connected, with 4 of the cubes as a larger cube and the other two attached together to it, there would be 3 large irregular faces (sides and back), 2 large cubic faces (bottom and front) and 3 rectangular faces (half cubes) as seen from the top. The total would be 8.
cubes
Hexahedrons have 6 faces. These include the rectangular prism, cuboids, and cubes.
1 cube has 6 faces therefore 236 cubes have 1,416 faces.
All cubes have six faces, regardless of size.
This is kind of neat. I drew a three dimensional cube. Then divided the faces into 16 squares per face. Then started counting which of those little cubes would have a painted face. I get: 1 red face - 24 cubes 2 red faces - 24 cubes 3 red faces - 8 cubes 4, 5, & 6 red faces - 0 cubes
Each cube has 6 faces. So 4 cubes together would have 24 faces.
six faces
6
no, all cubes have 6 faces. Just think about regular dice - they are cubes, and have the numbers 1 through 6. If a cube had 8 faces, the dice would have two empty faces!
I think the answer is 18 becausea cube has 6 face and 3 cubes have 18 faces.
24
12
It depends on how many cubes in the stack and what shape they form.
12...?