This one's a little tricky. Numbers can't start with zero, so "0323" is not really a 4-digit number (although you could use it as a Personal Identification Number for your ATM card). So, there are really only three digits that can be in the most significant place (the thousands place, in this case). Therefore, there are 3 x 4 x 4 x 4 = 192 unique 4-digit numbers that can be formed. Note that that amount allows for repetition of digits. If you are not allowed to repeat digits (the question placed no such restriction), then there are only 3 x 3 x 2 x 1 = 18 different numbers. By the way, this problem explores permutations, where the order of the elements matters. When the order doesn't matter, it's a combination. For example, if 123 and 321 are considered unique elements, then you are doing permutations. If they are considered the same element, you are doing combinations. Calculating the number of combinations is a bit trickier.
There are 60480 numbers.
There are 4^6 = 4096 such numbers.
125
13579
There are 900 of them.
There are 60480 numbers.
99999
There are 4^6 = 4096 such numbers.
8.
125
10
13579
There are 900 of them.
15 of them.
5040 numbers can be made.
there are 22
6, if you don't repeat any numbers.