xxyz
xyxz
xyzx
yxxz
yxzx
yzxx
if x is the digit that repeats then there are six possible placements of ten digits
y must be one of the remaining nine digits and z must be one of the further remaining eight digits
so 6x10x9x8 = 4320
(note: this supposes that leading zeros are included)
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500
If you're asking for 4 digit numbers where all four digits are odd, then the lowest number possible is 1111, and the highest is 9999. You only have 5 digits to work with. The answer is: 54 - 53 = 625 - 125 = 500.Subtract the 5 cubed for the numbers less than 1111, which are not four digits.
9347 is not a digit but four digits.
256 unless you count zero in which case its 625.
Nine digits, four positions becomes 94 or 6561.