If you're asking for 4 digit numbers where all four digits are odd, then the lowest number possible is 1111, and the highest is 9999. You only have 5 digits to work with. The answer is: 54 - 53 = 625 - 125 = 500.
Subtract the 5 cubed for the numbers less than 1111, which are not four digits.
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It is a permutation problem (any number can be used repeatedly), it will become 4 x 4 x 4 x 4 = 256 four digit numbers. If each number can only be used once, then the answer is 4 x 3 x 2 x 1 = 24 four digit numbers.
120 5-digit numbers can be made with the numbers 12345.
It is difficult to interpret exactly what you are trying to ask. If you allow your five digit number to have leading zeroes and do not allow negative numbers, then 00000 - 99999 = -99999 is the smallest number. If you do allow negative 5 digit numbers, then (-99999) - 99999 = -199998 is the smallest number.
To calculate the number of 4-digit numbers that can be formed using the digits 1, 3, 5, 7, and 9 without repetition, we use the permutation formula. Since there are 5 choices for the first digit, 4 choices for the second digit (as one digit has been used), 3 choices for the third digit, and 2 choices for the fourth digit, the total number of 4-digit numbers that can be formed is 5 x 4 x 3 x 2 = 120.
You have 5 choices for the 1st digit of the number. 4 choices for the 2nd digit and 3 choices for the 3rd and final digit. This means that there are 5 x 4 x 3 = 60 3-digit numbers that can be made from 5 different digits subject to each digit only being used once.