There are 4 ways to chose the first digit. Then because there is to be no repetition, there are 3 ways to choose the second. This means that there are 4 x 3 ways of setting down the first two digits 12 _ _ 13 _ _ 14 _ _ 21 _ _ 23 _ _ 24 _ _ 31 _ _ 32 _ _ 34 _ _ 41 _ _ 42 _ _ 43 _ _ .... now you can take it from there.
There are 28706 such combinations. 5456 of these comprise three 2-digit numbers, 19008 comprise two 2-digit numbers and two 1-digit numbers, 4158 comprise one 2-digit number and four 1-digit numbers and 84 comprise six 1-digit numbers.
Using only the numbers 1,3,5,7,9, and using each number only once, we have 5 options for the first digit, then 4 remaining options for the second, 3 remaining options for the third and 2 remaining options for the fourth. This means there are 5x4x3x2 ways to combine the digits 1,3,5,7,9 into a 4 digit number. 5x4x3x2=120, so there are 120 four digit numbers that can be made.
Add the two greatest possible four digit numbers. 9999 + 9999
7
Twelve of them.
1234, 2637, 7777, 2727 are examples of a four digit number. So any random four numbers are four digits.
4*3*2*1 = 24
1234
256
4 x 3 x 2 ie 24
1234?
1234, 1235 and 1236.
How many place combinations in a four digit number and all have to go in different spot example: 1234, 4321, 2134 etc. numbers can't change and have to stay four numbers?The answer would be 36 different combinations. This is simply the counting principle and it's easy for anyone to learn.
1234
The four digit multiples of 1234 are:1234 (1234x1)2468 (1234x2)3702 (1234x3)4936 (1234x4)6170 (1234x5)7404 (1234x6)8638 (1234x7)9872 (1234x8)Multiplying 1234 by 9 give the 5 digit number 11106, so the largest 4 digit multiple of 1234 is 9872.
Total possible 4-digit numbers= 1000, 1001,...,9999 = 9000 Total with same digit numbers = 1111,2222,...,9999 = 9 9000 - 9 = 8991