There are no four-digit perfect squares that are palindromes.
There is 90 four digit palindromes.
There are 90 four-digit palindromes
Nine. The sum of the digits must be a multiple of 9; because of the repeated digits, this is only possible if the first two digits add up to 9.
1221, 2112, 3003, 10401, 11211, 12021
The same as the number of two-digit numbers, since the last two digits must the same as the first two, only reversed. So I'll say there are 100 four-digit palindromes.
There is 90 four digit palindromes.
There are 90 four-digit palindromes
There are 90 four-digit palindromes
Nine. The sum of the digits must be a multiple of 9; because of the repeated digits, this is only possible if the first two digits add up to 9.
1221, 2112, 3003, 10401, 11211, 12021
81
The same as the number of two-digit numbers, since the last two digits must the same as the first two, only reversed. So I'll say there are 100 four-digit palindromes.
The same as the number of two-digit numbers, since the last two digits must the same as the first two, only reversed. So I'll say there are 100 four-digit palindromes.
A 9-digit palindrome has the structure where the first five digits determine the last four digits in reverse order. The first digit must be from 1 to 9 (to ensure it's a 9-digit number), giving us 9 options. The next four digits (the second to fifth digits) can each be any digit from 0 to 9, providing 10 options each. Therefore, the total number of 9-digit palindromes is (9 \times 10^4 = 90,000).
Colorado and wyoming
1024
1024