None. A reaction of ammonia does not produce any lead!
501 of them.
how many grams in 1.60kg
There are exactly 7.45 grams in 7.45 grams.
454 grams
The mass of water is 5,4 g.
The molar mass of oxygen is 16 g/mol, and the molar mass of carbon monoxide is 28 g/mol. For every 32 grams of oxygen reacted, 28 grams of carbon monoxide is formed according to the stoichiometry of the reaction. Therefore, from 35 grams of oxygen, (\frac{28}{32} \times 35 = 30.8) grams of carbon monoxide can be formed.
The balanced equation for the reaction is: 4 Na + O2 -> 2 Na2O. From the equation, 4 moles of sodium will react to form 2 moles of sodium oxide. Calculate the molar mass of Na2O (sodium oxide) to find out how many grams will be formed.
100, of course.
To find the mass of Cr formed, we first need to calculate the initial moles of Cr2O3 and Al. Next, we determine the limiting reactant based on stoichiometry. Knowing Al is the limiting reactant, we calculate the theoretical yield of Al2O3 formed, and then find the amount of Cr formed based on the stoichiometry of the reaction.
To calculate the amount of CO formed from 35.0 grams of oxygen, you need to determine the limiting reactant. First, convert 35.0 grams of O2 to moles. Then, use the balanced equation to calculate the moles of CO that can be formed from the moles of O2. Finally, convert the moles of CO to grams using the molar mass of CO.
First, convert the volume from cubic inches to cubic centimeters: 43.5 in^3 = 713.2 cm^3. Then, calculate the mass using the formula: mass = volume x density. So, mass = 713.2 cm^3 x 10.5 g/cm^3 = 7484.2 grams. Finally, convert grams to kilograms: 7484.2 g รท 1000 = 7.4842 kg.
The amount of product formed in a reaction is determined by the stoichiometry of the reaction. Without the specific reaction given, we can't determine the grams of product produced from 22.4g of a reactant. The balanced chemical equation is needed to calculate the amount of product formed.
To form ammonia (NH3) from nitrogen (N2) and hydrogen (H2), the balanced chemical equation is N2 + 3H2 โ 2NH3. This means that for every mole of nitrogen, 3 moles of hydrogen are required. Given that nitrogen is limiting in this case, all 70 grams of nitrogen will react with 210 grams (3 times 70) of hydrogen to form 70 grams of ammonia. This reaction will consume all the hydrogen, leaving no grams of hydrogen leftover.
cannot answer without more info.
25
160...cant quite grasp HOW though