None. When NH reacts there is no Pb involved and so there is none formed.
501 of them.
how many grams in 1.60kg
There are exactly 7.45 grams in 7.45 grams.
454 grams
100, of course.
The balanced equation for the reaction is: 4 Na + O2 -> 2 Na2O. From the equation, 4 moles of sodium will react to form 2 moles of sodium oxide. Calculate the molar mass of Na2O (sodium oxide) to find out how many grams will be formed.
First, convert the volume from cubic inches to cubic centimeters: 43.5 in^3 = 713.2 cm^3. Then, calculate the mass using the formula: mass = volume x density. So, mass = 713.2 cm^3 x 10.5 g/cm^3 = 7484.2 grams. Finally, convert grams to kilograms: 7484.2 g รท 1000 = 7.4842 kg.
The molar mass of oxygen is 16 g/mol, and the molar mass of carbon monoxide is 28 g/mol. For every 32 grams of oxygen reacted, 28 grams of carbon monoxide is formed according to the stoichiometry of the reaction. Therefore, from 35 grams of oxygen, (\frac{28}{32} \times 35 = 30.8) grams of carbon monoxide can be formed.
cannot answer without more info.
160...cant quite grasp HOW though
To find out how many grams of N2 are needed to produce 1.7 grams of NH3, you need to look at the balanced chemical equation for the reaction. For the reaction N2 + 3H2 -> 2NH3, the molar ratio of N2 to NH3 is 1:2. So you would need half the number of grams of N2 as NH3, which is 0.85 grams of N2.
You need 145,337 g silver nitrate.
To determine the amount of iron needed to react with 40 grams of iron(III) oxide, you should use the stoichiometry of the reaction. Calculate the molar mass of iron(III) oxide (Fe2O3) and determine the molar ratio between iron and iron(III) oxide in the balanced chemical equation. From there, you can calculate the amount of iron needed to fully react with 40 grams of iron(III) oxide.
No, Acids react with metals to form salts.
266,86 g aluminium chloride are obtained.
mass H2O =49.2g