There are 3 whose sum is 45 whose sum is 5
7 whose sum is 6
9 whose sum is 7
11 whose sum is 8
13 whose sum is 9
15 whose sum is 10
17 whose sum is 11
19 whose sum is 12
19 whose sum is 13
17 whose sum is 14
15 whose sum is 15
13 whose sum is 16
11 whose sum is 17
9 whose sum is 18
7 whose sum is 19
5 whose sum is 20
3 whose sum is 21
1 whose sum is 22.
There are 120 of them.
There are 20.
How many
There are 125 of them.
Since the first integer of the 3-digit numbers must be 2, the sum of the second and the third digits would be 13.Since the largest digit is 9, the 3-digit numbers could be 249, 294, 258, 285, 267, and 276.Thus, there are 6 integers between 200 and 300 whose sum of their digits is 15.
There are 120 of them.
There are none.
Counting all integers from 1 to 238 inclusive, there are 606 digits between these two numbers.
There are 20.
How many
There are 125 of them.
Two integers.
9*9*8*7 = 4536
Since the first integer of the 3-digit numbers must be 2, the sum of the second and the third digits would be 13.Since the largest digit is 9, the 3-digit numbers could be 249, 294, 258, 285, 267, and 276.Thus, there are 6 integers between 200 and 300 whose sum of their digits is 15.
There are infinitely many. For example, consider, 45, 451, 4511, 45111, 451111 and so on.
952 of them.
An infinite amount