Here is the way to solve this problem. Since the number has to be divisible by 7 and 4 this means that the number has to be divisible by 28. The smallest multiple of 28 is 281 and the largest multiple through 1-100 is 283. the since the one is inclusive you do 3-1+1 which equals 3. 3 integers is the answer.
9
There are 12 multiples of 8 in 1 to 100.
There are floor(100/8)=12 multiples of 8 between 1 and 100. 12/100*100=12%
There are 30 multiples of 30 that fall between 100 and 1,000.
20
128!
To find the integers between 100 and 150 that can be divided by either 3 or 4, we can first calculate the multiples of 3 and 4 in that range. The multiples of 3 between 100 and 150 are 102, 105, ..., 150, giving us 17 multiples. The multiples of 4 are 100, 104, ..., 148, which gives us 13 multiples. We also need to exclude the overlap (multiples of 12) which are 108, 120, 132, 144, totaling 4. Thus, the total count is 17 + 13 - 4 = 26 integers.
There are 67 multiples of 6 and 50 multiples of 8 in that range. Their total, 117, will include numbers that are both.
9
100% because all integers are multiples of 1
There are 12 multiples of 8 in 1 to 100.
10 is two in multiples of 2 to 100
There are floor(100/8)=12 multiples of 8 between 1 and 100. 12/100*100=12%
10 (they are 105, 126, 147, 168, 189, 210, 231, 252, 273, and 294)
200 and 300 are multiples of 100, among many others.
Usually all the integers (counting numbers) from 1 to 100.Usually all the integers (counting numbers) from 1 to 100.Usually all the integers (counting numbers) from 1 to 100.Usually all the integers (counting numbers) from 1 to 100.
101