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Here is the way to solve this problem. Since the number has to be divisible by 7 and 4 this means that the number has to be divisible by 28. The smallest multiple of 28 is 281 and the largest multiple through 1-100 is 283. the since the one is inclusive you do 3-1+1 which equals 3. 3 integers is the answer.

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[I]OVERHEAT

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4y ago
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6y ago

There are 3 such numbers.

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Q: How many integers from 1 through 100 are multiples of 4 and multiples of 7?
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