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Q: How many interior angles does a 18 gon have?

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Interior angles of a regular 18 gon (octdecagon) are 160o.

(18-2)*180 = 2880 degrees

The sum of the interior angles of an n-gon is given by the formula (n-2)(180) where n is the number of sides of the polygon. Thus, the sum of the interior angles of an 18-gon is (18-2)(180) = 2880.

(18-2)*180 = 2880 degrees

sum of interior angles = (sides - 2) * 180 = 16 * 180 = 1800 + 1080 = 2880 degrees

((2 x 18) - 4) x 90 = 2880o

(18-2)*180 = 16*180 = 2880 degrees.

Any angle that you like. The only constraint is that the sum of all 18 interior angles is 2880 degrees.

The sum of the interior angles of a polygon with n sides is (n-2)*180 degrees. So, the sum of the interior angles of an 18-gon is 16*180 = 2880 degrees. Subject to this sum, each particular angle can range from 0 to 360 (not inclusive) degrees. If you assume that all the angles of the 18-gon are equal, then you can say that each angle is 2880/18 = 160 degrees. However, there is absolutely no reason to support such an assumption.

The question makes no sense since a 18-gon cannot be added. You can add the measures of its interior or exterior angles, or the lengths of its sides, its diagonals and so on. But there is no such thing as a "sum of 18-gon".

Exterior angle measures 18 degrees Interior angle measures 162 degrees

It has 18 sides and interior angles,which of them are 160 degrees each and 2880 degrees total and is also called an octadecagon or octakaidecagon.

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