4Improved Answer:-30 feet of fencing will be needed
The circumference of a rectangle is 2*(length+width), so 2*(18+23) = 2*(41) = 82 Therefore, 82 feet of fencing is required to enclose the garden.
1 yd=3 ft. 16 yd= 48 ft. 294 - 48 = 246. 246 < 250, so the answer is NO.
Five feet, because five times four is 20.
This problem requires that you find the perimeter of the rectangle. As we know a rectangle has 4 sides with two sets of sides that are the same length. so two that are 24 ft. and two that are 12 feet. add them up: 24+24+12+12=72 ft.
4Improved Answer:-30 feet of fencing will be needed
839
The circumference of a rectangle is 2*(length+width), so 2*(18+23) = 2*(41) = 82 Therefore, 82 feet of fencing is required to enclose the garden.
40 yards
There are: 20 feet times 30 feet = 600 square feet
Anything up to 154.06 sq feet. The above value is attained by a circular garden. A quadrilateral garden has a maximum area of 121 sq feet but the minimum is as close to zero as you wish.
You will need 47.6 feet of fencing. Just add 13 + 13 + 10.8 + 10.8 together.
To find how many feet of fencing is needed, find the circumference of the garden. Use the formula Circumference = 2 pi(r) 2 x 3.14 x 2 6.28 x 2 12.56 Approximately 13 feet of fence is needed.
600=20 * 30
1 yd=3 ft. 16 yd= 48 ft. 294 - 48 = 246. 246 < 250, so the answer is NO.
If the garden is rectangular shape then the perimeter (total length of all sides) would be 80 feet. If you divide that by3 you would have 26.667 yards. So it sounds as though it would require at least more 2 yards of fencing.
Length = 20 feet Width = 5 feet 20+20+5 = 45 There was only 1 width of fencing because the other width was formed from the wall of the house.