The total amount of data (including the start and stop bit) in an 8-bit, 1024×
1024 image, is (1024)2×[8+2] bits. The total time required to transmit this image
over a 56K baud link is (512)^2 ×[8+2]/300 =8738.1 sec or about 145.6 min.
.25 would be 15 minutes.
She would run 2.4 miles in 18 minutes.
275/33 x 21 = 175 Therefore, 175 balls would be produced at the same rate in 21 minutes as there would be in 33 minutes.
214x24=5136 you would first multiply the day by 24 (to make it into hours) 5136/60 then you would divide by 60 (to make it into minutes minutes) and the answer would be 85.6
About 200 I would estimate
512x512x1 (256 = 2^8 = 1byte) * 8 (convert to bits) / 300 bits per second = 6990.50(6) seconds.
r u in room 206 right now
The opposite status is to receive. The failure to transmit would be to withhold or cut off.
They don't black out images they just don't transmit parts of the image that of no interest. ie why would you waste time and energy transmitting the part of a image where your thumb is when both time and ebergy are incredibly limited. Admittidly this is just a theory but it makes alot of sense.
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A flattened image has only one layer. After the image is flattened, it has the same appearance it had before. The difference is that all of the image contents are in a single layer without transparency. If there are any areas which are transparent through all of the layers of the original image, the background color is visible. By flattening an image we introduce significant changes to the structure of the image. It is normally only necessary when you would like to save an image in a format which does not support levels or transparency (an alpha channel).
No. It would be quite unusual for this to happen.
He was overly concerned with his image. I saw the cat's image in the mirror.
The image would appear distorted and not realistic
All glass windows both transmit and reflect light; the question is, what's the total light coming off of a piece of glass? If the inside of the car is dark and the exterior is bright, then the light coming out through the glass will be a tiny fraction of the light being reflected, and the primary image that you see will be the reflected image. But if it is dark outside and you turn on a light inside the car, then you'll see mirrored windows - but you would be plainly visible from outside!
This would be the opposite of a blurry or unfocused image.
each channel can only transmit signals in one direction signals are transmitted as rf waves can be used to transmit multiple signals at once