So far as I understand it, and in an effort to avoid actually getting tweezers and counting all the molecules, I gather that any molecule can be used with Avagadro's constant, even a mix of them, hence there are 6.02 x 10^23 molecules in a Mol and that would fill 22.4 litres. Therefore the answer is 6.02 x 10^23 / 22.4 = 2.69 x 10^22 molecules per litre at STP.
To check the answer, assuming that the molecular weight of N2 is 28 and the molecular weight of O2 is 32 and they are mixed in the ratio 79:21 then the total weight of a litre of air should be about (((79*28)+(21*32))/100) x (2.69 x 10^22) / (6.02 x 10^23) = 1.28g/litre and I think that given all of the rounding and guesswork involved, that agrees close enough for me with the 1.2kg/m^3 given on Wikipedia (given that there are 1000 litres in a cubic meter).
I'm sure there are more accurate answers to be had, but I don't have one to share.
That depends on the pressure and temperature of the air in the cubic meter. Any time you change the pressure or the temperature of a gas, you change the number of molecules in one cubic meter of it.
In one liter there are 100,000 hectograms. There are 100 hectograms in one gram, and that is multiplied by the 1,000 grams in a liter.
There are ten deciliters in one liter.
One thousand
A microliter (one-millionth of a liter).The first ten prefixes on the small side of the prefix list are :deciliter (one tenth of a liter)centiliter (one hundredth of a liter)milliter(one thousandth of a liter)microliter(one millionth of a liter)nanoliter (one billionth of a liter)picoliter (one trillionth of a liter)femtoliter (one quadrillionth of a liter)attoliter (one quintillionth of a liter)zeptoliter (one sextillionth of a liter)yoctoliter (one septillionth of a liter)
Ideal gas law: PV=nRT. number of moles is 0.0414335 moles. x avagadros number is 2.495x1022 molecules
1 liter of air is equivalent to approximately 0.0353 cubic feet of air.
If there are no air spaces (theoretically) it will be 1.5L
1 liter
The mass of the Earth's atmosphere is 5.25x10^21 grams. If we assume the molar mass of air is approximately 29 grams per mole we get:(5.25x10^21) multiplied by Avogadro's constant (6.02x10^23) and then divided by (29 grams/ mol) = 1.09x10^44 molecules of air in the atmosphere.
One liter of air at 101.325 equals on liter of air at 101.325. It is a trick question of sorts, because the metric unit of measurement "liter" is defined by said amount of matter in an atmosphere of 101.325 KPa.
Water because a liter is a measurement of space and not mass. Water occupying 1 liter of space is lots heavier than air occupying 1 liter of space. <><><><><> It depends on density. It is possible, given enough pressure, to have one liter of air weigh more than one liter of water.
not quite. some of the molecules fit between each other.
That depends on the pressure and temperature of the air in the cubic meter. Any time you change the pressure or the temperature of a gas, you change the number of molecules in one cubic meter of it.
The volume of one liter of air will increase because as the temperature increases, the air molecules gain energy and move faster, causing the air to expand. This relationship is described by Charles's Law, which states that the volume of a gas is directly proportional to its temperature in Kelvin, assuming constant pressure and amount of gas.
At STP (Standard Temperature and Pressure: 1 atmosphere of pressure, 0oC), one mole of any gas will occupy 22.4 liters of space. One mole of any substance contains 6.02 x 1023 particles (similar to how a dozen is 12 of anything). Air is about 21% oxygen, depending upon your location and local biotic and abiotic factors. So, at STP, 1 liter of air is about 0.21 liters of oxygen. To find out how many moles that represents, divide 0.21 by 22.4. Take that answer and multiply by 6.02 x 1023. It should be a very large number, on the order of 1021.
There are approximately 4.2 cups in one liter.