Best Answer

You only need to solve for the number of either nickels or dimes. You can subtract that number from 86 to find the other. Since dimes are worth more, let's solve for dimes; we'll use the variable "d". First, make a chart of what we know:

# dimes = "d"; 0.10 each; total cents in dimes = 10d

# nickels = 86 - d, 0.05 each; total cents in nickels = 5(86-d)

Total number/value of coins: total number is 86; total value $6.90, or 690 cents

Now set up the equation:

10d + 5(86-d) = 690

10d + (5 . 86) + (5 . - d) = 690

10d + 430 - 5d = 690

5d + 430 = 690

5d + 430 - 430 = 690 - 430

5d = 260

(1/5)5d = 260 (1/5)

d = 52

If there are 52 dimes, there must be 34 nickels (86 - 52 = 34).

Let's check our work:

52 dimes = $5.20

34 nickels = $1.70

$5.20 + 1.70 = $6.90

Q: How many nickels and dimes make 6.90 with 86 coins?

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