To find the number of integers between 1 and 400 that are divisible by 7, we can use the formula for finding the number of integers in an arithmetic sequence. The first term in this sequence is 7, the last term is 399, and the common difference is also 7. Using the formula (last term - first term) / common difference + 1, we get (399 - 7) / 7 + 1 = 56. Therefore, there are 56 numbers between 1 and 400 that are divisible by 7.
There are 22 numbers between 400 and 600 that are divisible by nine.
400 / 7 = 57, so there are 57 multiples of 7 under 400.
7x3 = 21 All numbers from 1-400 (399 total) that are factors of 21: 399/21 = 19
There are 8 numbers: 312, 324, 336, 348, 360, 372, 384, 396.
The first number is 403 and the last number in the series would be 793. There are 31 of them.
There are 22 numbers between 400 and 600 that are divisible by nine.
400 / 7 = 57, so there are 57 multiples of 7 under 400.
57 of them.
400 divided by 7 is 57. That would be your answer.
7x3 = 21 All numbers from 1-400 (399 total) that are factors of 21: 399/21 = 19
200/5=40 200/9=22.2 400/5=80 400/9=44.4 They is only 2 numbers. y'all do the rest.
400/7 = 57.1 (approx) so there are 57 numbers.400/7 = 57.1 (approx) so there are 57 numbers.400/7 = 57.1 (approx) so there are 57 numbers.400/7 = 57.1 (approx) so there are 57 numbers.
There are 8 numbers: 312, 324, 336, 348, 360, 372, 384, 396.
57, ranging from 7 to 399.
The first number is 403 and the last number in the series would be 793. There are 31 of them.
56 of them.
One: 235.