To find the number of integers between 1 and 400 that are divisible by 7, we can use the formula for finding the number of integers in an arithmetic sequence. The first term in this sequence is 7, the last term is 399, and the common difference is also 7. Using the formula (last term - first term) / common difference + 1, we get (399 - 7) / 7 + 1 = 56. Therefore, there are 56 numbers between 1 and 400 that are divisible by 7.
There are 22 numbers between 400 and 600 that are divisible by nine.
400 / 7 = 57, so there are 57 multiples of 7 under 400.
7x3 = 21 All numbers from 1-400 (399 total) that are factors of 21: 399/21 = 19
To find numbers divisible by 3 between 400 and 500, we first identify the first and last multiples of 3 within this range. The first multiple of 3 after 400 is 402, and the last multiple before 500 is 498. To calculate how many numbers are divisible by 3 in this range, we subtract the first multiple from the last (498 - 402 = 96) and then divide by 3 to account for the interval between each multiple (96 / 3 = 32). Therefore, there are 32 numbers between 400 and 500 that are divisible by 3.
There are 8 numbers: 312, 324, 336, 348, 360, 372, 384, 396.
There are 22 numbers between 400 and 600 that are divisible by nine.
400 / 7 = 57, so there are 57 multiples of 7 under 400.
57 of them.
400 divided by 7 is 57. That would be your answer.
7x3 = 21 All numbers from 1-400 (399 total) that are factors of 21: 399/21 = 19
200/5=40 200/9=22.2 400/5=80 400/9=44.4 They is only 2 numbers. y'all do the rest.
400/7 = 57.1 (approx) so there are 57 numbers.400/7 = 57.1 (approx) so there are 57 numbers.400/7 = 57.1 (approx) so there are 57 numbers.400/7 = 57.1 (approx) so there are 57 numbers.
There are 8 numbers: 312, 324, 336, 348, 360, 372, 384, 396.
57, ranging from 7 to 399.
The first number is 403 and the last number in the series would be 793. There are 31 of them.
56 of them.
One: 235.